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Bunuel
If |4x - 7| = |3x + 2|, which of the following is a possible value of x?

A. -2
B. 1
C. 5/7
D. 7/5
E. 3

Given, |4x - 7| = |3x + 2|
Squaring both sides,

\((4x - 7)^2 = (3x + 2)^2\)
Or, \(16x^2-56x+49=9x^2+4+12x\)
Or, \(7x^2-68x+45=0\)
Or, \(x^2-\frac{68}{7}x+\frac{45}{7}=0\)
Or, \((x-\frac{5}{7})(x-9)=0\)
Or, \(x=\frac{5}{7} or, x=9\)

Ans. (C)
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Should we not substitute the value back in the modulus and confirm whether the solution holds true? It holds true for x=9 but not for x=5/7.
Am I missing something?
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Should we not substitute the value back in the modulus and confirm whether the solution holds true? It holds true for x=9 but not for x=5/7.
Am I missing something?

Hi Ritz123,
Since the equation deals with only absolute function, you needn't to check the solution by substitution.
At x=\(\frac{5}{7}\), LHS: \(|4x-7|=|4*\frac{5}{7}-7|=|\frac{20}{7}-7|\)=\(|\frac{20-49}{7}|\)=\(|\frac{-29}{7}|\)=\(\frac{29}{7}\)

RHS: \(|3x+2|=|3*\frac{5}{7}+2|=|\frac{15}{7}+2|=|\frac{15+14}{7}|=|\frac{29}{7}|=\frac{29}{7}\)

LHS=RHS.
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Here's how I got to the right answer choice.

l 4x - 7 l = - l 3x+2 l or l 4x-7 l = l 3x +2 l

If we try to calculate the x for the first case, we find that x = 5/7, which is one of the possible answer choices. Hence, C.
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adkikani

You are right.

adkikani
ammuseeru

One of efficient ways of solve modulus on both sides is below approach:

|a| = |b| reduces to
a = b or a = -b

hence the problem becomes:
4x-7 = 3x+2
or x=9

Or
4x-7 = -3x-2
or 7x = 5
or x=5/7

gmatbusters VeritasKarishma Gladiator59 Abhishek009 chetan2u

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This would be the fastest approach. Good work adkikani :-)

Another longer approach would be squaring both sides and solving the quadratic to get two solutions. I would recommend solving by that approach as well to get a better understanding of such questions.

Regards,
Gladi

adkikani
ammuseeru

One of efficient ways of solving modulus on both sides is below approach:

|a| = |b| reduces to
a = b or a = -b

hence the problem becomes:
4x-7 = 3x+2
or x=9

Or
4x-7 = -3x-2
or 7x = 5
or x=5/7

gmatbusters VeritasKarishma Gladiator59 Abhishek009 chetan2u
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adkikani
ammuseeru

One of efficient ways of solving modulus on both sides is below approach:

|a| = |b| reduces to
a = b or a = -b

hence the problem becomes:
4x-7 = 3x+2
or x=9

Or
4x-7 = -3x-2
or 7x = 5
or x=5/7

gmatbusters VeritasKarishma Gladiator59 Abhishek009 chetan2u

Yes, this is the approach using the concept of absolute values. Though in these questions, I feel squaring both sides is faster. Since it is absolute value on both sides, no negative values are possible. So even if we are dealing with inequalities, it doesn't matter.
Given |a| = |b|, you can safely say that a^2 = b^2
Given |a| < |b|, you can safely say that a^2 < b^2
Given |a| > |b|, you can safely say that a^2 > b^2
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