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If 4x  7 = 3x + 2, which of the following is a possible value of
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10 Aug 2018, 02:44
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If 4x  7 = 3x + 2, which of the following is a possible value of
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Updated on: 10 Aug 2018, 03:50
Bunuel wrote: If 4x  7 = 3x + 2, which of the following is a possible value of x?
A. 2 B. 1 C. 5/7 D. 7/5 E. 3 Given, 4x  7 = 3x + 2 Squaring both sides, \((4x  7)^2 = (3x + 2)^2\) Or, \(16x^256x+49=9x^2+4+12x\) Or, \(7x^268x+45=0\) Or, \(x^2\frac{68}{7}x+\frac{45}{7}=0\) Or, \((x\frac{5}{7})(x9)=0\) Or, \(x=\frac{5}{7} or, x=9\) Ans. (C)
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Originally posted by PKN on 10 Aug 2018, 02:57.
Last edited by PKN on 10 Aug 2018, 03:50, edited 1 time in total.



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Re: If 4x  7 = 3x + 2, which of the following is a possible value of
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10 Aug 2018, 03:43
Bunuel wrote: If 4x  7 = 3x + 2, which of the following is a possible value of x? Case 1 :4x  7 = 3x + 2 x = 9 ( Not in option) Case 2 :4x  7 = 3x  2 7x = 5 x = 5 / 7 Hence, C.
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Re: If 4x  7 = 3x + 2, which of the following is a possible value of
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16 Aug 2018, 20:21
Should we not substitute the value back in the modulus and confirm whether the solution holds true? It holds true for x=9 but not for x=5/7. Am I missing something?



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Re: If 4x  7 = 3x + 2, which of the following is a possible value of
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16 Aug 2018, 20:34
Ritz123 wrote: Should we not substitute the value back in the modulus and confirm whether the solution holds true? It holds true for x=9 but not for x=5/7. Am I missing something? Hi Ritz123, Since the equation deals with only absolute function, you needn't to check the solution by substitution. At x=\(\frac{5}{7}\), LHS: \(4x7=4*\frac{5}{7}7=\frac{20}{7}7\)=\(\frac{2049}{7}\)=\(\frac{29}{7}\)=\(\frac{29}{7}\) RHS: \(3x+2=3*\frac{5}{7}+2=\frac{15}{7}+2=\frac{15+14}{7}=\frac{29}{7}=\frac{29}{7}\) LHS=RHS.
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Re: If 4x  7 = 3x + 2, which of the following is a possible value of
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08 Nov 2018, 04:21
Here's how I got to the right answer choice. l 4x  7 l =  l 3x+2 l or l 4x7 l = l 3x +2 l If we try to calculate the x for the first case, we find that x = 5/7, which is one of the possible answer choices. Hence, C.
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Re: If 4x  7 = 3x + 2, which of the following is a possible value of
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29 Dec 2018, 16:46
Bunuel wrote: If 4x  7 = 3x + 2, which of the following is a possible value of x?
A. 2 B. 1 C. 5/7 D. 7/5 E. 3 . Hello BunuelCould you post detail solution for this question. Thanks,



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If 4x  7 = 3x + 2, which of the following is a possible value of
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30 Dec 2018, 05:49
ammuseeruOne of efficient ways of solving modulus on both sides is below approach: a = b reduces to a = b or a = b hence the problem becomes: 4x7 = 3x+2 or x=9 Or 4x7 = 3x2 or 7x = 5 or x=5/7 gmatbusters VeritasKarishma Gladiator59 Abhishek009 chetan2u
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Re: If 4x  7 = 3x + 2, which of the following is a possible value of
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30 Dec 2018, 07:04



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Re: If 4x  7 = 3x + 2, which of the following is a possible value of
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30 Dec 2018, 07:19
This would be the fastest approach. Good work adkikani Another longer approach would be squaring both sides and solving the quadratic to get two solutions. I would recommend solving by that approach as well to get a better understanding of such questions. Regards, Gladi adkikani wrote: ammuseeruOne of efficient ways of solving modulus on both sides is below approach: a = b reduces to a = b or a = b hence the problem becomes: 4x7 = 3x+2 or x=9 Or 4x7 = 3x2 or 7x = 5 or x=5/7 gmatbusters VeritasKarishma Gladiator59 Abhishek009 chetan2u
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Re: If 4x  7 = 3x + 2, which of the following is a possible value of
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01 Jan 2019, 02:49
adkikani wrote: ammuseeruOne of efficient ways of solving modulus on both sides is below approach: a = b reduces to a = b or a = b hence the problem becomes: 4x7 = 3x+2 or x=9 Or 4x7 = 3x2 or 7x = 5 or x=5/7 gmatbusters VeritasKarishma Gladiator59 Abhishek009 chetan2u Yes, this is the approach using the concept of absolute values. Though in these questions, I feel squaring both sides is faster. Since it is absolute value on both sides, no negative values are possible. So even if we are dealing with inequalities, it doesn't matter. Given a = b, you can safely say that a^2 = b^2 Given a < b, you can safely say that a^2 < b^2 Given a > b, you can safely say that a^2 > b^2
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