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If 7 and 8 are factors of 60n, what is the minimum value of n?

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If 7 and 8 are factors of 60n, what is the minimum value of n? [#permalink] New post   19 Apr 2010, 15:13
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If 7 and 8 are factors of 60n, what is the minimum value of n?

(A) 2
(B) 3
(C) 7
(D) 14
(E) 56
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D
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Re: If 7 and 8 are factors of 60n, what is the minimum value of n? [#permalink] New post   19 Apr 2010, 15:24
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60n/7*8 should be integer => 2*2*3*5*n/7*2*2*2 = 3*5*n/14 must be an integer

for this to be true n must multiple of 14, thus min of n = 14

hence D
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Re: If 7 and 8 are factors of 60n, what is the minimum value of n? [#permalink] New post   19 Apr 2010, 22:58
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TheGmatTutor wrote:
If 7 and 8 are factors of 60n, what is the minimum value of n?

(A) 2
(B) 3
(C) 7
(D) 14
(E) 56


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D

i suppose 60n = 60*n in that case, minimum value will be combination of missing factor 7 and one 2 to be divisible by 7 and 8 i.e. 14
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Re: If 7 and 8 are factors of 60n, what is the minimum value of n? [#permalink] New post   15 Sep 2016, 08:13
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TheGmatTutor wrote:
If 7 and 8 are factors of 60n, what is the minimum value of n?

(A) 2
(B) 3
(C) 7
(D) 14
(E) 56


56 should be the HCF of 60n and 7*8
Factorise 60n = 2*2*3*5*n, while 7*8=2*2*2*7....since 7&8 do not have any factor in common...
In 60n and 7*8, 4 is the hcf so n should be 56/4=14..
D
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Re: If 7 and 8 are factors of 60n, what is the minimum value of n? [#permalink] New post   20 Nov 2019, 13:20
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Re: If 7 and 8 are factors of 60n, what is the minimum value of n? [#permalink]
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