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19 Apr 2010, 15:13
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If 7 and 8 are factors of 60n, what is the minimum value of n?
(A) 2
(B) 3
(C) 7
(D) 14
(E) 56
(A) 2
(B) 3
(C) 7
(D) 14
(E) 56
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19 Apr 2010, 15:24
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60n/7*8 should be integer => 2*2*3*5*n/7*2*2*2 = 3*5*n/14 must be an integer
for this to be true n must multiple of 14, thus min of n = 14
hence D
for this to be true n must multiple of 14, thus min of n = 14
hence D
19 Apr 2010, 22:58
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TheGmatTutor
If 7 and 8 are factors of 60n, what is the minimum value of n?
(A) 2
(B) 3
(C) 7
(D) 14
(E) 56
i suppose 60n = 60*n in that case, minimum value will be combination of missing factor 7 and one 2 to be divisible by 7 and 8 i.e. 14 (A) 2
(B) 3
(C) 7
(D) 14
(E) 56
