Bunuel
If 8 Machine A's and 10 Machine B's take 3 and 4 hours respectively to complete a job, how many minutes will it take for 6 Machine A's and 15 Machine B's working together to complete the same job?
A. 66 minutes
B. 76 minutes
C. 96 minutes
D. 106 minutes
E. 120 minutes
If 8 Machine A's take 3 hours to complete the work, 1 Machine A will take 8 times the time.
- Time taken by 1 Machine A to complete the task = 3 * 8 = 24 hours
If 10 Machine B's take 4 hours to complete the work, 1 Machine B will take 10 times the time.
- Time taken by 1 Machine B to complete the task = 10 * 4 = 40 hours
Let's assume that the task is LCM(24,40) = 120 units
- Work done by 1 Machine A in 1 hour (rate of Machine A) = 120/24 = 5 units
- Work done by 1 Machine B in 1 hour (rate of Machine B) = 120/40 = 3 units
- Work done by 6 Machine A's in 1 hour = 6 * 5 = 30 units
- Work done by 15 Machine B's in 1 hour = 15 * 5 = 45 units
Total work done by 6 Machine A's + 15 Machine B's in 1 hour = 30 +45 = 75 units
Time taken to complete the work = \(\frac{120 }{ 75} = (1 + \frac{45}{75}\)) hours
Time in minutes = \(60(1 + \frac{45}{75}) = 60 + (9*4) = 60 + 36 = 96\) minutes
Option C