Bunuel
If a > 0 and b < 0, which of the following statements are true about the values of x that solve the equation \(x^2 − ax + b = 0\) ?
I. They have opposite signs.
II. Their sum is greater than Zero.
III. Their product equals -b
A. I only
B. II only
C. I and II only
D. I and III only
E. I, II and III
If the quadratic equation is \(ax^2+bx+c=0\),
Sum of roots = \(\frac{-b}{a}\)
Product of roots = \(\frac{c}{a}\)
I. They have opposite signs.
II. Their sum is greater than Zero.
III. Their product equals -b
\(x^2 -ax + b = 0\) is the quadratic equation here.
Sum of roots = \(\frac{(-a)}{1}=a\)
Product of roots = \(\frac{b}{1}=b\)
I. They have opposite signs.
Product of the two roots is b. => \(x_1*x_2=b<0\).
Thus the product of two roots is NEGATIVE, and it is possible only when they have opposite sign.
True
II. Their sum is greater than Zero.
\(x_1+x_2=a>0\).
True
III. Their product equals -b
\(x_1*x_2=b\).
False
I and II
C