Last visit was: 23 Apr 2026, 15:58 It is currently 23 Apr 2026, 15:58
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
tejal777
Joined: 25 Oct 2008
Last visit: 09 Jan 2012
Posts: 360
Own Kudos:
6,991
 [48]
Given Kudos: 100
Location: Kolkata,India
Posts: 360
Kudos: 6,991
 [48]
1
Kudos
Add Kudos
46
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
flyingbunny
Joined: 14 Aug 2009
Last visit: 18 Aug 2010
Posts: 49
Own Kudos:
153
 [6]
Given Kudos: 13
Posts: 49
Kudos: 153
 [6]
5
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
General Discussion
User avatar
yezz
User avatar
Retired Moderator
Joined: 05 Jul 2006
Last visit: 26 Apr 2022
Posts: 830
Own Kudos:
Given Kudos: 49
Posts: 830
Kudos: 1,686
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
fozzzy
Joined: 29 Nov 2012
Last visit: 17 May 2015
Posts: 573
Own Kudos:
7,003
 [2]
Given Kudos: 543
Posts: 573
Kudos: 7,003
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
For statement 2

we get \(b^2=c^2\) then \(b^2 - C^2 = 0\) >> \((b-c) (b+c) = 0\)

Why is this manipulation incorrect?
User avatar
Zarrolou
Joined: 02 Sep 2012
Last visit: 11 Dec 2013
Posts: 842
Own Kudos:
5,187
 [2]
Given Kudos: 219
Status:Far, far away!
Location: Italy
Concentration: Finance, Entrepreneurship
GPA: 3.8
Posts: 842
Kudos: 5,187
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
fozzzy
For statement 2

we get \(b^2=c^2\) then \(b^2 - C^2 = 0\) >> \((b-c) (b+c) = 0\)

Why is this manipulation incorrect?

That is not incorrect.

You get \((b-c) (b+c) = 0\) so one (or both) terms equal zero. However we know that both b and c are positive, so (b+c) is positive as well, so b-c=0
Hence \(a(b-c)=0\) => sufficient
avatar
fozzzy
Joined: 29 Nov 2012
Last visit: 17 May 2015
Posts: 573
Own Kudos:
Given Kudos: 543
Posts: 573
Kudos: 7,003
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Zarrolou


That is not incorrect.

You get \((b-c) (b+c) = 0\) so one (or both) terms equal zero. However we know that both b and c are positive, so (b+c) is positive as well, so b-c=0
Hence \(a(b-c)=0\) => sufficient


So basically B+C is just redundant information once we solve till that point? Hence that case is ignored and we focus on the second case?
User avatar
Zarrolou
Joined: 02 Sep 2012
Last visit: 11 Dec 2013
Posts: 842
Own Kudos:
5,187
 [1]
Given Kudos: 219
Status:Far, far away!
Location: Italy
Concentration: Finance, Entrepreneurship
GPA: 3.8
Posts: 842
Kudos: 5,187
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
fozzzy
Zarrolou


That is not incorrect.

You get \((b-c) (b+c) = 0\) so one (or both) terms equal zero. However we know that both b and c are positive, so (b+c) is positive as well, so b-c=0
Hence \(a(b-c)=0\) => sufficient


So basically B+C is just redundant information once we solve till that point? Hence that case is ignored and we focus on the second case?

I do not know what you mean by "redundant information", but yes: we know that \(b+c\) cannot be zero, so the other term (\(b-c\)) must be zero.

All we get from \(b^2-c^2=0\) in this problem is that \(b-c=0\)
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
810,864
 [4]
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,864
 [4]
1
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
If a > 0, b > 0 and c > 0, is a(b - c) = 0?

Is \(a(b - c) = 0\)? --> is \(a=0\) or \(b-c=0\)? Since given that \(a > 0\), then the questions basically asks whether \(b-c=0\).

(1) b - c = c - b --> \(2b-2c=0\) --> \(b-c=0\). Sufficient.

(2) b/c = c/b --> \(b^2=c^2\) --> \((b-c)(b+c)=0\) --> \(b+c=0\) or \(b-c=0\) but since \(b\) and \(c\) are positive, then \(b+c>0\). Therefore \(b-c=0\). Sufficient.

Answer: D.
User avatar
AmritaSarkar89
Joined: 22 Feb 2016
Last visit: 02 Jul 2025
Posts: 64
Own Kudos:
Given Kudos: 208
Location: India
Concentration: Economics, Healthcare
GMAT 1: 690 Q42 V47
GMAT 2: 710 Q47 V39
GPA: 3.57
GMAT 2: 710 Q47 V39
Posts: 64
Kudos: 52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Whoo!!! another super tricky question which can take you off the hooks during exam.
The simplest way to look at this question is we have 3 conditions a>0, b>0 and c>0 so thy are positive numbers but can be integers or fraction. (always proceed with this thought process - even if irrelevant here, it helps in the long run).
Question asks if a(b-c)=0 now we know a>0 thus a not equal to 0 hence b-c=0 or B=C

Statement 1
B-c=0
B=c Sufficient

Statement 2
c^2=B^2
|C|=|B|
since they are both greater than 0 hence c=b
Suffcienet
Answer is D.

+kudos I need to unlock the exams :)
User avatar
anairamitch1804
Joined: 26 Oct 2016
Last visit: 20 Apr 2019
Posts: 502
Own Kudos:
Given Kudos: 877
Location: United States
Concentration: Marketing, International Business
Schools: HBS '19
GMAT 1: 770 Q51 V44
GPA: 4
WE:Education (Education)
Schools: HBS '19
GMAT 1: 770 Q51 V44
Posts: 502
Kudos: 3,605
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If a > 0, b > 0 and c > 0, is a(b - c) = 0?

Is \(a(b - c) = 0\)? --> is \(a=0\) or \(b-c=0\)? Since given that \(a > 0\), then the questions basically asks whether \(b-c=0\).

(1) b - c = c - b --> \(2b-2c=0\) --> \(b-c=0\). Sufficient.

(2) b/c = c/b --> \(b^2=c^2\) --> \((b-c)(b+c)=0\) --> \(b+c=0\) or \(b-c=0\) but since \(b\) and \(c\) are positive, then \(b+c>0\). Therefore \(b-c=0\). Sufficient.

Answer: D.

Nice Explanation Bunuel. Thanks for sharing your approach.
User avatar
Nixondutta
Joined: 24 Apr 2017
Last visit: 10 Aug 2018
Posts: 40
Own Kudos:
Given Kudos: 83
Status:The journey is always more beautiful than the destination
Affiliations: Computer Science
Location: India
Concentration: Statistics, Strategy
GMAT 1: 570 Q40 V28
GPA: 3.14
GMAT 1: 570 Q40 V28
Posts: 40
Kudos: 78
Kudos
Add Kudos
Bookmarks
Bookmark this Post
tejal777
If a > 0, b > 0 and c > 0, is a(b - c) = 0?

(1) b - c = c - b
(2) b/c = c/b


This is a yes/ no question.
After simplifying the equation we get,
if b=c then b-c = 0. so the question depends on two equation.
1. Whether a is 0.
or 2. b=c.

option 1 says b = c . sufficient.
option 2 says b^2=c^c. no as b>0 and c>0, b=c. sufficient.
avatar
aakash13111989
Joined: 28 Apr 2020
Last visit: 22 Sep 2021
Posts: 18
Own Kudos:
Given Kudos: 56
Posts: 18
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel Nice approach and explanation. Its a tricky question. Thanks
User avatar
Basshead
Joined: 09 Jan 2020
Last visit: 07 Feb 2024
Posts: 907
Own Kudos:
Given Kudos: 431
Location: United States
Posts: 907
Kudos: 323
Kudos
Add Kudos
Bookmarks
Bookmark this Post
tejal777
If \(a > 0\), \(b > 0\) and \(c > 0\), is \(a(b - c) = 0\)?


(1) \(b - c = c - b\)

(2) \(\frac{b}{c} = \frac{c}{b}\)

Is a = 0 or b = c?

(1) \(b - c = c - b\)

\(2b = 2c\)
\(b = c\\
\)
SUFFICIENT.

(2) \(\frac{b}{c} = \frac{c}{b}\)
\(2b = 2c\)
\(b = c\)

SUFFICIENT.

Answer is D.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,963
Own Kudos:
Posts: 38,963
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109785 posts
498 posts
212 posts