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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # If a^(1/2) > b^2 > c^4, which of the following could be true?

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Math Expert V
Joined: 02 Sep 2009
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If a^(1/2) > b^2 > c^4, which of the following could be true?  [#permalink]

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Difficulty:   55% (hard)

Question Stats: 46% (02:02) correct 54% (01:50) wrong based on 57 sessions

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If $$\sqrt{a} > b^2 > c^4$$, which of the following could be true?

I. a > b > c
II. c > b > a
III. a > c > b

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III only

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Re: If a^(1/2) > b^2 > c^4, which of the following could be true?  [#permalink]

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given condition possible
a= 4 , b= 1/2 , c=1/3
a=1/4, b=1/5, c= 1/3
a=4,b=1/3, c=1/5
IMO D ; a > c > b & a > b > c

Bunuel wrote:
If $$\sqrt{a} > b^2 > c^4$$, which of the following could be true?

I. a > b > c
II. c > b > a
III. a > c > b

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III only

Are You Up For the Challenge: 700 Level Questions
Manager  S
Joined: 19 Jan 2019
Posts: 110
Re: If a^(1/2) > b^2 > c^4, which of the following could be true?  [#permalink]

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1
Condition 1
- a>b>c
Possible for values such as a= 200 , b= 3, c= 1 .

Condition 2-
C>b>a , possible for values such as c= 0.5, b= 0.49 , a = 0.48..

Condition 3-
A>c>b, possible for values such as a= 10000000, c= 1, b= -10..

Imo E.

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Re: If a^(1/2) > b^2 > c^4, which of the following could be true?  [#permalink]

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Bunuel wrote:
If $$\sqrt{a} > b^2 > c^4$$, which of the following could be true?

I. a > b > c
II. c > b > a
III. a > c > b

A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III only

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Since √a > b^2 > c^4, squaring all 3 quantities, we have a > b^4 > c^8. Since both b^4 and c^8 are nonnegative and a is greater than both of them, then a must be positive. Furthermore, if both b and c are at least 1, then a > b^4 > c^8 means a > b > c. For example, we can let a = 25, b = 2 and c = 1. We see that √a = 5, b^2 = 4 and c^4 = 1 satisfies √a > b^2 > c^4. Thus, statement I could be true.

In order for c > b > a, c and b must be positive since a is positive. However, as mentioned earlier, if both b and c are at least 1, then a > b > c. So the only way that it is possible for c > b > a is for both c and b to be between 0 and 1; in that case, a must also be between 0 and 1. For example, if a = ¼, b = ⅓, and c = ½, we have √a = 1/2, b^2 = 1/9 and c^4 = 1/16 satisfies √a > b^2 > c^4. Thus, II could be true.

If both b and c are negative, obviously, a is greater than either of them since a is positive. However, since b^2 > c^4, square rooting both sides, we have |b| > c^2. Therefore, it’s possible for c > b and still have |b| > c^2. For example, if we let b = -2 and c = -1 and we can still have a = 25, we have √a = 5, b^2 = 4 and c^4 = 1 satisfies √a > b^2 > c^4. But in this case, we have a > c > b. Thus, III could be true.

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If you find one of my posts helpful, please take a moment to click on the "Kudos" button. Re: If a^(1/2) > b^2 > c^4, which of the following could be true?   [#permalink] 12 Nov 2019, 20:10
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