Bunuel wrote:
If a^2 = b, is 1 > a > 0?
(1) 1 > b > 0
(2) a > b
Kudos for a correct solution.
IMO : B
Statement 1: 0< b< 1
if b lies in 0< b< 1 then
a can lie in 0< a< 1 or -1 < a< 0.
For eg: if b = 1/4 then a can be 1/2 or -1/2 .
Not suff
Statement 2: a > b
Given \(a^2 = b\) i.e
b >=0. And if a>b then
a must also be >=0If a>b then
for a>1 then \(a^2 > b\). They cannot be equal
so a must be in interval 0<a<1 PS: a cannot be equal to "0" or "1" since it violates the statement 2: a>b
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