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Sub 505 (Easy)|   Algebra|   Exponents|      
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jotapepe
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If a and b are both greater than 1, then (√a^2b)(√ab^2) = Updated on: 02 Nov 2021, 22:49
Originally posted by jotapepe on 02 Nov 2021, 14:05.
Last edited by chetan2u on 02 Nov 2021, 22:49, edited 1 time in total.
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86% (00:52) correct 14% (01:23) wrong based on 293 sessions

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If a and b are both greater than 1, then \((\sqrt{a^2b})(\sqrt{ab^2})\) =


a) ab
b) \(a^2b^2\)
c) \(\sqrt{ab}\)
d) \(ab\sqrt{ab}\)
e) \(a^2b^2\sqrt{ab}\)
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chetan2u
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GMAT Focus 1: 735 Q90 V89 DI81
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If a and b are both greater than 1, then (√a^2b)(√ab^2) = 02 Nov 2021, 22:43
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jotapepe
If a and b are both greater than 1, then (√a^2b)(√ab^2) =


a) ab
b) a^2b^2
c) √ab
d) ab√ab
e) a^2b^2√ab
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Please follow rules for posting a question. Provide OA and proper formatting to be done.
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chetan2u
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GMAT Focus 1: 735 Q90 V89 DI81
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If a and b are both greater than 1, then (√a^2b)(√ab^2) = 02 Nov 2021, 22:49
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jotapepe
If a and b are both greater than 1, then \((\sqrt{a^2b})(\sqrt{ab^2})\) =


a) ab
b) \(a^2b^2\)
c) \(\sqrt{ab}\)
d) \(ab\sqrt{ab}\)
e) \(a^2b^2\sqrt{ab}\)
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\((\sqrt{a^2b})(\sqrt{ab^2})\) =\((\sqrt{a^2b*ab^2})\) =\(ab\sqrt{ab}\)


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cantryboy
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If a and b are both greater than 1, then (√a^2b)(√ab^2) = 23 Jan 2022, 20:08
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chetan2u
jotapepe
If a and b are both greater than 1, then \((\sqrt{a^2b})(\sqrt{ab^2})\) =


a) ab
b) \(a^2b^2\)
c) \(\sqrt{ab}\)
d) \(ab\sqrt{ab}\)
e) \(a^2b^2\sqrt{ab}\)


\((\sqrt{a^2b})(\sqrt{ab^2})\) =\((\sqrt{a^2b*ab^2})\) =\(ab\sqrt{ab}\)


D
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can you please explain the final answer...I don't understand why there is still a square root left in the the answer, thanks!
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chetan2u
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If a and b are both greater than 1, then (√a^2b)(√ab^2) = 23 Jan 2022, 20:45
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cantryboy
chetan2u
jotapepe
If a and b are both greater than 1, then \((\sqrt{a^2b})(\sqrt{ab^2})\) =


a) ab
b) \(a^2b^2\)
c) \(\sqrt{ab}\)
d) \(ab\sqrt{ab}\)
e) \(a^2b^2\sqrt{ab}\)


\((\sqrt{a^2b})(\sqrt{ab^2})\) =\((\sqrt{a^2b*ab^2})\) =\(ab\sqrt{ab}\)

can you please explain the final answer...I don't understand why there is still a square root left in the the answer, thanks!
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Whatever is two times in square root comes out.
Since there are 3 a, 2 of them will move out but one will remain inside square root. Similarly for b.

\(\sqrt{a*a*b*b*b*a}=\sqrt{a*a*b*b}*\sqrt{a*b}=ab\sqrt{ab}\)
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If a and b are both greater than 1, then (√a^2b)(√ab^2) = 23 Jan 2022, 21:19
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If you have a good sense of "taking" numbers/variables out of square roots that's one way to go. Another way would be to simply plug in values for a and b and make sure the same value holds true for the answer choice you select.

Quick tip: Be a little careful, since multiple answer choices may give the correct value when you plug values in sometimes.
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If a and b are both greater than 1, then (√a^2b)(√ab^2) = 08 Feb 2025, 13:20
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\((\sqrt{a^2b})(\sqrt{ab^2})\)
= \((\sqrt{a^3b^3})\)
= \(ab(\sqrt{ab})\)
jotapepe
If a and b are both greater than 1, then \((\sqrt{a^2b})(\sqrt{ab^2})\) =


a) ab
b) \(a^2b^2\)
c) \(\sqrt{ab}\)
d) \(ab\sqrt{ab}\)
e) \(a^2b^2\sqrt{ab}\)
Show more
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