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DLMD
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DLMD
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First rule says if a b in a set then ab in a set and second says if -a in set then a in set.

1) in this statement "2 is in the set" doesn't follow any of the above 2 rules, so can't tell if 12 is also in the set....insuff

2) -3 falls under the 2nd rule i.e. -a then a . So we can determine the set as (3,-3). As 12 is not part of that we can ans the ques ---"No"...Suff


Hence "B"
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DLMD
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banerjeea_98
First rule says if a b in a set then ab in a set and second says if -a in set then a in set.

1) in this statement "2 is in the set" doesn't follow any of the above 2 rules, so can't tell if 12 is also in the set....insuff

2) -3 falls under the 2nd rule i.e. -a then a . So we can determine the set as (3,-3). As 12 is not part of that we can ans the ques ---"No"...Suff


Hence "B"


Banerjeea:

the questions says a and -a in a set, but didn't mention they are the range of a set, right?

then set can be (-3, 20) so 12, 3 and -3 are all in the set.

I might think too much, but please clarify for me if you could

thx
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banerjeea_98
First rule says if a b in a set then ab in a set and second says if -a in set then a in set.

1) in this statement "2 is in the set" doesn't follow any of the above 2 rules, so can't tell if 12 is also in the set....insuff

2) -3 falls under the 2nd rule i.e. -a then a . So we can determine the set as (3,-3). As 12 is not part of that we can ans the ques ---"No"...Suff


Hence "B"


Mmm...your logic is good but blows me away. When I read the question, I was thinking there are other numbers in the set, not just only a and b in the set. Excellent! :good

DLMD, I totally agree with banerjeea_98's solution.
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DLMD
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Jinino:

I guess Baner is right but I just cannot figure out why a and -a defines range

:oops: :oops: :oops:
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From condition 1, if 2 is in set, then -2 is in set.
From condition 2, if (2, -2) in set then -4 is in set and so on...

If -3 is in set, 3 is in set.

Combining the sentences, since -3 and -4 are in the set, 12 is part of the set.

Answer is C

Am I making any assumptions not listed in the conditions??
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jinino
banerjeea_98
First rule says if a b in a set then ab in a set and second says if -a in set then a in set.

1) in this statement "2 is in the set" doesn't follow any of the above 2 rules, so can't tell if 12 is also in the set....insuff

2) -3 falls under the 2nd rule i.e. -a then a . So we can determine the set as (3,-3). As 12 is not part of that we can ans the ques ---"No"...Suff


Hence "B"

Mmm...your logic is good but blows me away. When I read the question, I was thinking there are other numbers in the set, not just only a and b in the set. Excellent! :good

DLMD, I totally agree with banerjeea_98's solution.

i still don't understand why is it the range. what about b.. we were only talking abt being 3 right..
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I think the answer should be C.

if 2 and -3 are in the set, it implies that -6 is in the set (by rule 1) which means that 2*(-6) = -12 is in the set. By rule 2, this means that 12 is in the set.
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I think you guys have a valid counterpoint...Don't know what to do with this question. :shock:
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vprabhala
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i would think its C. whats the OA?
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I would go with "I don't know what the heck you guys are talking about"...that's my OA but look this is what I'm getting:


{a,b, then ab} and {-a the a}

So if one of the numbers is 2

For choice A {-2, 2} and {-2, b, then -2b}...know can b = -6 based on any data given....not in my opinion


For choice B {-3, 3} and {-3, b, then -3b}..know can b = -4 based on the data given...not in my opinion

Furthermore why did I even assign a to equal -2 or -3 because for all I know a = 2 or 3 or b could equal +/- 2 or 3 so either this is E or this is one of those eeny, meeny, miiney mo questions.



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