mrcentauri wrote:
so what I have done wrong here is assume both were the same integers?
is this how a problem like this should be solved? according to
manhattan prep strategy, you should try different numbers i.e. -/+ even/odd within the constraints of the problem (although this is a data sufficiency strategy)
how am I able to deduce a = b?, why could a not equal 3 and b = 5?
the question asks if and b ARE integers,
does this mean they are both the same or could be different?
do you see where I am coming from?
are you saying the trick is the wording of the question? a AND b are integers meaning or implying they are the same? because if so then the first answer would be non-zero
where am I going wrong here?
Hi
mrcentauriFirst you need to understand the language of the question. The question specifically says, which of the following \(CANNOT\) be \(0\)
So any choice which CAN or CANNOT be 0 must be eliminated. We only need option which will
NEVER be \(0\) irrespective of the value of \(a\) or \(b\)
Now you can test as many values as you may like for a & b but in all the options except E, there is a possibility to get 0. Hence E is our answer because it CANNOT be 0 for any combination of a & b.
as the question does not provide any restriction between a & b so a=b is a possible assumption