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If A and B are positive integers and 24 x A x B is a perfect square, which of the following CANNOT be possible?
I. Both A and B are odd. II. AB is a perfect square. III. Both A and B are divisible by 6.
I think it is 24*A*B and not the 4 digit no 24AB
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Bunuel
If A and B are positive integers and 24AB is a perfect square, then which of the following cannot be possible?

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I, II, and III

I. Both A and B are odd.
we need 2 as a factor in order to arrive at square therefore not possible

II. AB is a perfect square
let us assume it to be 36 then it doesn't become perfect square any possibility from fom 16 to 81 not possible

III. Both A and B are divisible by 6

Therefore IMO D
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Bunuel
If A and B are positive integers and 24AB is a perfect square, then which of the following cannot be possible?

I. Both A and B are odd.
II. AB is a perfect square
III. Both A and B are divisible by 6

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I, II, and III




This question is a part of Are You Up For the Challenge: 700 Level Questions collection.
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Alright look. 2401 is the only perfect square in the range 2400-2499
So A = 0, B = 1 is the only possible soln. However they say A, B are both positive integers. 0 is not positive. So we have no solns.

1. Both A and B are odd. If both A and B are odd, 24AB is not a perfect square. So it cannot be possible
2) If AB is a perfect square then this would have been possible if we allow 0 as a value. But we don't so again, not possible
3) Not possible again as only soln is A = 0, B = 1

All 3 statements are not possible. In fact, no matter what you write in any statements, it won't make the truth of the original proposition. 24AB can be a perfect square if and only if A = 0, B =1. But 0 is not in our domain of values. All 3 statements cannot be true regardless.

If anything, this is a bad bad question since the original proposition (24AB being a perfect square) can never be true for positive integers A, B

Bunuel please correct the answer if i'm right
Bunuel
If A and B are positive integers and 24AB is a perfect square, then which of the following cannot be possible?

I. Both A and B are odd.
II. AB is a perfect square
III. Both A and B are divisible by 6

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I, II, and III
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Not Bunuel but I'm confident that the question means 24AB as in 24 * A * B, not a 4-digit number with digits 2, 4, A, and B. Interpreting it that way makes both statements 1) and 2) impossible.


Pranavsawant
Alright look. 2401 is the only perfect square in the range 2400-2499
So A = 0, B = 1 is the only possible soln. However they say A, B are both positive integers. 0 is not positive. So we have no solns.

1. Both A and B are odd. If both A and B are odd, 24AB is not a perfect square. So it cannot be possible
2) If AB is a perfect square then this would have been possible if we allow 0 as a value. But we don't so again, not possible
3) Not possible again as only soln is A = 0, B = 1

All 3 statements are not possible. In fact, no matter what you write in any statements, it won't make the truth of the original proposition. 24AB can be a perfect square if and only if A = 0, B =1. But 0 is not in our domain of values. All 3 statements cannot be true regardless.

If anything, this is a bad bad question since the original proposition (24AB being a perfect square) can never be true for positive integers A, B

Bunuel please correct the answer if i'm right

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Not Bunuel but I'm confident that the question means 24AB as in 24 * A * B, not a 4-digit number with digits 2, 4, A, and B. Interpreting it that way makes both statements 1) and 2) impossible.




Yes, 24AB means 24 * A * B. If 24AB were a four-digit number, it would have been explicitly mentioned. Without such clarification, "24AB" can only represent "24 * A * B", as the multiplication sign (*) is typically omitted.
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Bunuel answer choice D should be
(D) I and III only
Please correct

If A and B are positive integers and 24AB is a perfect square, then which of the following cannot be possible?

I. Both A and B are odd.
II. AB is a perfect square
III. Both A and B are divisible by 6

(A) I only
(B) II only
(C) III only
(D) I and III only
(E) I, II, and III

2401 is the only perfect square of the form 24AB.
Therefore, AB = 01 which is a perfect square, A is even, B is NOT divisible by 6.

IMO D
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Here 24AB means 2*4*A*B apparently lol
Even I made the same reasoning mistake above.
Kinshook
Bunuel answer choice D should be
(D) I and III only
Please correct

If A and B are positive integers and 24AB is a perfect square, then which of the following cannot be possible?

I. Both A and B are odd.
II. AB is a perfect square
III. Both A and B are divisible by 6

(A) I only
(B) II only
(C) III only
(D) I and III only
(E) I, II, and III

2401 is the only perfect square of the form 24AB.
Therefore, AB = 01 which is a perfect square, A is even, B is NOT divisible by 6.

IMO D
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Interesting but then I don't get why they would put it as 24AB
They should've just said it as 8*A*B
24AB is such a misleading way to represent 8*A*B

But yeah D is obvious in that case. Would never expect an OG question to trip us like this
Bunuel


Yes, 24AB means 24 * A * B. If 24AB were a four-digit number, it would have been explicitly mentioned. Without such clarification, "24AB" can only represent "24 * A * B", as the multiplication sign (*) is typically omitted.
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