Last visit was: 19 Nov 2025, 08:11 It is currently 19 Nov 2025, 08:11
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
IgnitedMind
Joined: 28 Aug 2008
Last visit: 10 Mar 2009
Posts: 53
Own Kudos:
Posts: 53
Kudos: 217
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
FN
User avatar
Current Student
Joined: 28 Dec 2004
Last visit: 07 May 2012
Posts: 1,576
Own Kudos:
Given Kudos: 2
Location: New York City
Concentration: Social Enterprise
Schools:Wharton'11 HBS'12
Posts: 1,576
Kudos: 675
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
scthakur
Joined: 17 Jun 2008
Last visit: 30 Jul 2009
Posts: 609
Own Kudos:
Posts: 609
Kudos: 449
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
spriya
Joined: 17 Jun 2008
Last visit: 18 Nov 2010
Posts: 617
Own Kudos:
Posts: 617
Kudos: 3,059
Kudos
Add Kudos
Bookmarks
Bookmark this Post
IgnitedMind
If a and b are positive, is (a^-1 + b^-1)^-1 less than (a^-1 * b^-1)^-1 ?

1) a = 2b

2) a + b > 1


A
B
C
D
E

OA will follow, please discuss
scthakur
ab/(a+b) < ab
question is :
ab/(a+b) < ab or ab(1/(a+b) -1 )<0 ????


(1) says a=2b , a=2b does not guarantee a+b>1 hence above expr can be +vbe or -ve INSUFFI

(2)a+b>1 does not say a and b have same signs or opposite ,in both cases different values for the expr.

(1) and (2) => SUFFI both are of same signs and again a+b>1 proves the relation given above

IMO C
User avatar
amitdgr
Joined: 30 Jun 2008
Last visit: 21 May 2013
Posts: 536
Own Kudos:
Given Kudos: 1
Posts: 536
Kudos: 3,124
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The best way to solve would be, simplify the question as much as possible

from the question we get to know that a and b are positive

so ab/(a+b) < ab can be written as ab(a+b) > ab and since ab is positive, we can divide both sides by ab ...

the simplified question is (a+b) > 1 ?

statement 1 says a = 2b ... this does not help me in telling whether a+b>1

incidentally statement 2 gives us the info directly that (a+b) > 1

so 2 is sufficient

Answer is B
User avatar
stallone
Joined: 31 Jul 2008
Last visit: 25 Nov 2008
Posts: 118
Own Kudos:
Posts: 118
Kudos: 164
Kudos
Add Kudos
Bookmarks
Bookmark this Post
i think its B !

because we need either ab<0 (impossible as a N b both are +ve) OR a+b>1

first stamnt doesnt help 2b+b may or may not be >1

2 stmnt proves a+b>1

hence B
User avatar
x2suresh
Joined: 07 Nov 2007
Last visit: 18 Aug 2012
Posts: 715
Own Kudos:
Given Kudos: 5
Location: New York
Posts: 715
Kudos: 3,139
Kudos
Add Kudos
Bookmarks
Bookmark this Post
IgnitedMind
If a and b are positive, is (a^-1 + b^-1)^-1 less than (a^-1 * b^-1)^-1 ?

1) a = 2b

2) a + b > 1


A
B
C
D
E

OA will follow, please discuss

ab/(a+b) < ab
Question is ab(a+b)>ab?

1) a=2b.. a+b can be <1 or a+b>1
not sufficient
2) a+b>1
also ab is positive.
ab(a+b)>ab is always true.
sufficient.


B
User avatar
ssandeepan
Joined: 09 Jul 2007
Last visit: 13 Jun 2010
Posts: 116
Own Kudos:
Posts: 116
Kudos: 1,740
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(a^-1 + b^-1)^-1 less than (a^-1 * b^-1)^-1 ?

simplifyling the expression ab/(a+b) < ab ? or is 1 < ( a+ b) , which is stated in option 2 directly

so IMO B
User avatar
spriya
Joined: 17 Jun 2008
Last visit: 18 Nov 2010
Posts: 617
Own Kudos:
Posts: 617
Kudos: 3,059
Kudos
Add Kudos
Bookmarks
Bookmark this Post
oops i didnt read the questio properly again!!!



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderators:
Math Expert
105389 posts
GMAT Tutor
1924 posts