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# If a#b = a^2 – a, where b ≥ 0, what is the value of (–4)#4?

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Math Expert
Joined: 02 Sep 2009
Posts: 51281
If a#b = a^2 – a, where b ≥ 0, what is the value of (–4)#4?  [#permalink]

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29 Jul 2018, 23:50
1
00:00

Difficulty:

15% (low)

Question Stats:

81% (01:06) correct 19% (00:45) wrong based on 21 sessions

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If $$a#b = a^2*\sqrt{b} - a$$, where b ≥ 0, what is the value of (–4)#4?

(A) –36
(B) –28
(C) 12
(D) 28
(E) 36

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Joined: 02 Aug 2009
Posts: 7112
Re: If a#b = a^2 – a, where b ≥ 0, what is the value of (–4)#4?  [#permalink]

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30 Jul 2018, 01:28
1
Bunuel wrote:
If $$a#b = a2\sqrt{b} - a$$, where b ≥ 0, what is the value of (–4)#4?

(A) –36
(B) –28
(C) 12
(D) 28
(E) 36

Bunuel, can you pl check, I think there is a typo because none of the answer matches in the given function..
It should be $$a#b=a^2\sqrt{b}-a$$
In -4#4, a=-4 and b=4..
Therefore $$-4#4=(-4)^2\sqrt{4}-(-4)=4*4*2+4=32+4=36$$

E

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1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

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Math Expert
Joined: 02 Sep 2009
Posts: 51281
Re: If a#b = a^2 – a, where b ≥ 0, what is the value of (–4)#4?  [#permalink]

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30 Jul 2018, 01:44
chetan2u wrote:
Bunuel wrote:
If $$a#b = a2\sqrt{b} - a$$, where b ≥ 0, what is the value of (–4)#4?

(A) –36
(B) –28
(C) 12
(D) 28
(E) 36

Bunuel, can you pl check, I think there is a typo because none of the answer matches in the given function..
It should be $$a#b=a^2\sqrt{b}-a$$
In -4#4, a=-4 and b=4..
Therefore $$-4#4=(-4)^2\sqrt{4}-(-4)=4*4*2+4=32+4=36$$

E

Posted from my mobile device

____________
You are right. Edited. Thank you.
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Re: If a#b = a^2 – a, where b ≥ 0, what is the value of (–4)#4? &nbs [#permalink] 30 Jul 2018, 01:44
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