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Updated on: 10 Jun 2015, 04:35
Originally posted by tjerkrintjema on 10 Jun 2015, 04:04.
Last edited by Bunuel on 10 Jun 2015, 04:35, edited 2 times in total.
Last edited by Bunuel on 10 Jun 2015, 04:35, edited 2 times in total.
Renamed the topic, edited the question and added the OA.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
64% (01:51) correct
36%
(01:58)
wrong
based on 162
sessions
History
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Time
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If a + b + c > 0, is c > 2?
(1) c - a > b + 2
(2) a + b + 3 < 0
Source Mindful GMAT
(1) c - a > b + 2
(2) a + b + 3 < 0
Source Mindful GMAT
10 Jun 2015, 04:07
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Okay I'm not sure about the answer,
But looking at statement 1
a+b+c > 0
c-a > b+ 2
-------------+
b+2c > b+2
2c > 2
c > 1
Therefore not sufficient as it can be 2 as well
Statement 2
a+b+c > 0
a+b+3 < 0
Divide the bottom equation by -1 to switch signs
So
a+b+c > 0
-a-b-3 > 0
------------+
c-3 > 0
c > 3
Therefore I believe answer should be B.
But looking at statement 1
a+b+c > 0
c-a > b+ 2
-------------+
b+2c > b+2
2c > 2
c > 1
Therefore not sufficient as it can be 2 as well
Statement 2
a+b+c > 0
a+b+3 < 0
Divide the bottom equation by -1 to switch signs
So
a+b+c > 0
-a-b-3 > 0
------------+
c-3 > 0
c > 3
Therefore I believe answer should be B.
10 Jun 2015, 04:42
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tjerkrintjema
In the stem and in both statements we have a + b (in (1) c - a > b + 2 is the same as c > a + b + 2). To simplify, denote a + b as x.
If x + c > 0, is c > 2?
(1) c > x + 2. Sum x + c > 0 and c > x + 2 (we can sum inequalities if their signs are in the same direction):
(x +c) + c > 0 + (x + 2)
c > 1.
Not sufficient.
(2) x + 3 < 0. Subtract x + 3 < 0 from x + c > 0 (we can subtract inequalities if their signs are in the opposite directions):
(x + c) - (x + 3) > 0 - 0.
c > 3.
Sufficient.
Answer: B.
Hope it's clear.
