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If a, b, c, and d are consecutive even integers and a < b < c < d, the
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03 Jul 2018, 23:03
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76% (00:28) correct 24% (00:27) wrong based on 75 sessions
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Re: If a, b, c, and d are consecutive even integers and a < b < c < d, the
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03 Jul 2018, 23:13
(a+2 + a+3)  (a + a+1) = 4 (B)



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Re: If a, b, c, and d are consecutive even integers and a < b < c < d, the
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03 Jul 2018, 23:45
Bunuel wrote: If a, b, c, and d are consecutive even integers and a < b < c < d, then a + b is how much less than c + d ?
A. 2 B. 4 C. 6 D. 8 E. 10 We can write the consecutive even integers in the form: a=2n b=2n+2 c=2n+4 d=2n+6 where n is a nonnegative integer. \(n\geq{0}\) Now a+b=4n+2 & c+d=4n+10 So, (c+d)(a+b)=4n+10(4n+2)=8 Ans. D
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Re: If a, b, c, and d are consecutive even integers and a < b < c < d, the
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05 Jul 2018, 04:19
Solution Given:• a, b, c, and d are consecutive integers • a < b < c < d
To find: Approach and Working: • The four positive integers (a, b, c and d) can be represented as 2n, 2n+2, 2n+4, 2n+6 respectively (since a<b<c<d), where n is an integer • Value of (c+d) = (2n+4 + 2n+6) = 4n +10 • Value of (a+b) = (2n + 2n+2) = 4n + 2 • Thus, (c+d) –(a+b) = (4n+10) – (4n+2) = 8
Therefore, the value of (a+b) is 8 less than that of (c+d) Hence, the correct answer is option D. Answer: D
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If a, b, c, and d are consecutive even integers and a < b < c < d, the
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05 Jul 2018, 13:52
Bunuel wrote: If a, b, c, and d are consecutive even integers and a < b < c < d, then a + b is how much less than c + d ?
A. 2 B. 4 C. 6 D. 8 E. 10 \(a, b, c, d\) \(2, 4, 6, 8\) \((a+b)=(2+4)=6\) \((c+d)=(6+8)=14\) \((c+d)(a+b)=(146)=8\) The difference between and range of four consecutive integers will always be the same. Test if in doubt with another number set: \(6, 8, 10, 12\) \((22  14) = 8\) Answer D
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Re: If a, b, c, and d are consecutive even integers and a < b < c < d, the
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09 Jul 2018, 19:57
Bunuel wrote: If a, b, c, and d are consecutive even integers and a < b < c < d, then a + b is how much less than c + d ?
A. 2 B. 4 C. 6 D. 8 E. 10 We can let a, b, c, and d equal 2, 4, 6, and 8 respectively. a + b = 2 + 4 = 6 c + d = 6 + 8 = 14 Thus, a + b is 14  6 = 8 less than c + d. Answer: D
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Re: If a, b, c, and d are consecutive even integers and a < b < c < d, the
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09 Jul 2018, 21:09
I use the substitution method in such a question:So use whatever consecutive even numbers that come to your mind. For eg.2,4,6,8 By simple math in the mind,we get (6+8)(2+4)=8,which is the answer. I hope it helps
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