Bunuel
If a, b, c and d are four different positive integers selected from 1 to 25, then the highest possible value of \(\frac{(a+b)+(c+d)}{(a+b)+(c−d)}\) would be:
A. 47
B. 49
C. 51
D. 96
E. 101
\(\frac{(a+b)+(c+d)}{(a+b)+(c−d)}\)
\(\frac{(a+b)+(c+d)}{(a+b)-(d-c)}\)
We need to make the denominator the least for the value of the fraction to be greatest.
Before we proceed with further analysis, there are few things to that we can observe.
- All the answers choices are positive integers so the numerator has to be a multiple of the denominator.
- The numerator will always be positive integer, so the denominator also has to be positive integer.
- We are subtracting (d - c) from (a + b), we need to keep the net result positive, at the same time ensure that the denominator is least. At this point, we can conclude that the denominator is 1. Even if we cannot say for sure, its always worth a try to see if the denominator can be 1.
We need to maximize d - c, so that we subtract the maximum possible from (a+b).
Let's take d = 25 & c = 1. d - c = 24
Can we have a + b = 25 ? yes when a = 13 and b = 12
So the denominator = 1
Numerator = (13 + 12) + (25 + 1) = 26 + 25 = 51.
Option C