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27 Jul 2022, 04:15
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (00:45) correct
29%
(01:18)
wrong
based on 105
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If a certain object has been moving at the constant rate of x meters per minute, how many meters has the object moved in the last y seconds?
A. \(\frac{xy}{60}\)
B. \(\frac{60x}{y}\)
C. \(\frac{x}{60y}\)
D. \(\frac{60}{xy}\)
E. \(60xy\)
A. \(\frac{xy}{60}\)
B. \(\frac{60x}{y}\)
C. \(\frac{x}{60y}\)
D. \(\frac{60}{xy}\)
E. \(60xy\)
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27 Jul 2022, 04:55
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Bunuel
If a certain object has been moving at the constant rate of x meters per minute, how many meters has the object moved in the last y seconds?
A. \(\frac{xy}{60}\)
B. \(\frac{60x}{y}\)
C. \(\frac{x}{60y}\)
D. \(\frac{60}{xy}\)
E. \(60xy\)
A. \(\frac{xy}{60}\)
B. \(\frac{60x}{y}\)
C. \(\frac{x}{60y}\)
D. \(\frac{60}{xy}\)
E. \(60xy\)
x m/min = x/60 m/s
so distance travelled in y meters = (x/60)*y = xy/60
hence option A is correct.
27 Jul 2022, 05:22
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Speed = Distance/time
Thus, Distance = Speed*Time
Speed = x m/mim = x/60 m/s
Distance = x*y/60 m/s
Thus, the correct option is A.
Thus, Distance = Speed*Time
Speed = x m/mim = x/60 m/s
Distance = x*y/60 m/s
Thus, the correct option is A.
