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06 Jun 2025, 02:38
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C
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If a certain school will buy computers at a fixed price of x dollars each and computer desks at a fixed price of y dollars each, how many dollars will the school pay for each computer?
(1) The school will pay a total of $2,200 if it buys 2 computers and 1 computer desk at these fixed prices.
(2) The school will pay a total of $5,400 if it buys 5 computers and 2 computer desks at these fixed prices.
ID: 700405
Data Insights Review 2025-26
(1) The school will pay a total of $2,200 if it buys 2 computers and 1 computer desk at these fixed prices.
(2) The school will pay a total of $5,400 if it buys 5 computers and 2 computer desks at these fixed prices.
ID: 700405
Data Insights Review 2025-26
06 Jun 2025, 06:04
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If a certain school will buy computers at a fixed price of x dollars each and computer desks at a fixed price of y dollars each, how many dollars will the school pay for each computer?
(1) The school will pay a total of $2,200 if it buys 2 computers and 1 computer desk at these fixed prices.
This gives the equation: 2x + y = 2,200. There are multiple (x, y) pairs that satisfy this equation. For example, x = 1 and y = 2,198 or x = 2 and y = 2,196. Not sufficient.
(2) The school will pay a total of $5,400 if it buys 5 computers and 2 computer desks at these fixed prices.
This gives the equation: 5x + 2y = 5,400. Again, multiple (x, y) pairs satisfy this. For example, x = 2 and y = 2,695 or x = 4 and y = 2,690. Not sufficient.
(1)+(2) We have two distinct linear equations, so we can solve for both unknowns. Sufficient. Just to illustrate: multiplying the first equation by 2 and subtracting it from the second one gives x = 5,400 - 2,200*2 = 1,000.
Answer: C.
(1) The school will pay a total of $2,200 if it buys 2 computers and 1 computer desk at these fixed prices.
This gives the equation: 2x + y = 2,200. There are multiple (x, y) pairs that satisfy this equation. For example, x = 1 and y = 2,198 or x = 2 and y = 2,196. Not sufficient.
(2) The school will pay a total of $5,400 if it buys 5 computers and 2 computer desks at these fixed prices.
This gives the equation: 5x + 2y = 5,400. Again, multiple (x, y) pairs satisfy this. For example, x = 2 and y = 2,695 or x = 4 and y = 2,690. Not sufficient.
(1)+(2) We have two distinct linear equations, so we can solve for both unknowns. Sufficient. Just to illustrate: multiplying the first equation by 2 and subtracting it from the second one gives x = 5,400 - 2,200*2 = 1,000.
Answer: C.
09 Jun 2025, 08:51
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Pretty straightforward systems of equation thinking. Just double check you're not in an exceptional case like a redundant equation or a scenario where it's possible to isolate a variable and narrow down the posibilities for the other variable. But this is straightforward:
