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11 Oct 2019, 04:24
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If a coin has an equal probability of landing heads up or tails up each time it is flipped, what is the probability that the coin will land heads up exactly twice in 3 consecutive flips?
(A) 0.125
(B) 0.25
(C) 0.375
(D) 0.50
(E) 0.666
(A) 0.125
(B) 0.25
(C) 0.375
(D) 0.50
(E) 0.666
11 Oct 2019, 04:30
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Bunuel
If a coin has an equal probability of landing heads up or tails up each time it is flipped, what is the probability that the coin will land heads up exactly twice in 3 consecutive flips?
(A) 0.125
(B) 0.25
(C) 0.375
(D) 0.50
(E) 0.666
(A) 0.125
(B) 0.25
(C) 0.375
(D) 0.50
(E) 0.666
total fair chances ; 1/2*1/2*1/2 = 1/8 ; .125
and getting heads twice in 3 flips we have
HHT; HTH; THH ; 3 ways so .125*3 ; .375
IMO C
11 Oct 2019, 04:37
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P(getting heads) = P(getting tails) = 0.5 (50%)
We have to determine the probability of getting exactly 2 Heads in three consecutive flips. Therefore, we have H, H and T. We have to see the possible cases.
1) HTH
2) HHT
3) THH
Thus, total test cases with exactly 2 H are: 3
Also, the total cases will be 8.
P(H=O) + P(H=1) + P(H=2) + P(H=3)
= 1 + 3 + 3 + 1
= 8
Thus, the required probability = 3/8= 0.375
(C)
Posted from my mobile device
We have to determine the probability of getting exactly 2 Heads in three consecutive flips. Therefore, we have H, H and T. We have to see the possible cases.
1) HTH
2) HHT
3) THH
Thus, total test cases with exactly 2 H are: 3
Also, the total cases will be 8.
P(H=O) + P(H=1) + P(H=2) + P(H=3)
= 1 + 3 + 3 + 1
= 8
Thus, the required probability = 3/8= 0.375
(C)
Posted from my mobile device
