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If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int

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If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int  [#permalink]

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New post 19 Sep 2018, 20:49
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If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured into a right circular cylindrical glass with radius 2 inches, how many inches high will the soymilk reach? (Assume that the capacity of the glass is greater than the volume of the soymilk.)


(A) \(8\)

(B) \(16\)

(C) \(\frac{4}{\pi}\)

(D) \(\frac{8}{\pi}\)

(E) \(\frac{16}{\pi}\)

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Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int  [#permalink]

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New post 19 Sep 2018, 23:29
Volume of soymilk = 4*2*4 = 32cm^3

π(2)^2h = 32
h=8/π

My guess
Ans : D
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Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int  [#permalink]

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New post 20 Sep 2018, 03:00
Bunuel wrote:
If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured into a right circular cylindrical glass with radius 2 inches, how many inches high will the soymilk reach? (Assume that the capacity of the glass is greater than the volume of the soymilk.)


(A) \(8\)

(B) \(16\)

(C) \(\frac{4}{\pi}\)

(D) \(\frac{8}{\pi}\)

(E) \(\frac{16}{\pi}\)


Volume of Milk \(= (1/2)*(4*2*8) = 32\) cubic inches

Volume of Cylinder \(= πr^2h = π*2^2*h\)

Now, \(= πr^2h = π*2^2*h = 32\)
i.e. \(h = 8/π\)

Answer:: Option D
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Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int  [#permalink]

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New post 25 May 2020, 03:34
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Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int   [#permalink] 25 May 2020, 03:34

If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int

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