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# If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int

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If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int  [#permalink]

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19 Sep 2018, 20:49
1
00:00

Difficulty:

25% (medium)

Question Stats:

76% (00:49) correct 24% (01:02) wrong based on 34 sessions

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If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured into a right circular cylindrical glass with radius 2 inches, how many inches high will the soymilk reach? (Assume that the capacity of the glass is greater than the volume of the soymilk.)

(A) $$8$$

(B) $$16$$

(C) $$\frac{4}{\pi}$$

(D) $$\frac{8}{\pi}$$

(E) $$\frac{16}{\pi}$$

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Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int  [#permalink]

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19 Sep 2018, 23:29
Volume of soymilk = 4*2*4 = 32cm^3

π(2)^2h = 32
h=8/π

My guess
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Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int  [#permalink]

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20 Sep 2018, 03:00
Bunuel wrote:
If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured into a right circular cylindrical glass with radius 2 inches, how many inches high will the soymilk reach? (Assume that the capacity of the glass is greater than the volume of the soymilk.)

(A) $$8$$

(B) $$16$$

(C) $$\frac{4}{\pi}$$

(D) $$\frac{8}{\pi}$$

(E) $$\frac{16}{\pi}$$

Volume of Milk $$= (1/2)*(4*2*8) = 32$$ cubic inches

Volume of Cylinder $$= πr^2h = π*2^2*h$$

Now, $$= πr^2h = π*2^2*h = 32$$
i.e. $$h = 8/π$$

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Re: If a half-full 4-inch by 2-inch by 8-inch box of soymilk is poured int &nbs [#permalink] 20 Sep 2018, 03:00
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