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Bunuel
If a is an integer, is a < 4 ?

(1) \(10^{(-2a + 2)} < 0.001\)

(2) \(10^{(-2a)} > 0.0001\)


Statement 1:

We can write as \(10^{(-2a + 2}) < 10^{(-3)}\)

As bases are same we can compare powers,

\(-2a + 2 < -3\) ,

\(-2a < -5\);

\(a > 2.5\)

\(" a "\) can be less than or anything more than 4 so NOT SUFFICIENT.

Statement 2:

Same as above,

\(-2a > -4\) ;

\(a < 2\)

For sure we can say \(a < 4\)

SUFFICIENT (B)

There was a typo in the second statement. Edited. Sorry for that.
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Bunuel
If a is an integer, is a < 4 ?

(1) \(10^{(-2a + 2)} < 0.001\)

(2) \(10^{(-2a)} < 0.0001\)



(1) \(10^{(-2a + 2)} < 0.001.............10^{(-2a + 2)} < 10^{(-3)}\)
Equating the powers, \(-3>-2a+2........2a>5........a>\frac{5}{2}\)
when a=3, Yes, but when a=10, answer is no.

(2) \(10^{(-2a)} < 0.0001.............10^{(-2a + 2)} < 10^{(-4)}\)
Equating the powers, \(-4>-2a........2a>4........a>2\)
when a=3, Yes, but when a=10, answer is no.

Combined..
when a=3, Yes, but when a=10, answer is no.

E
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Bunuel
If a is an integer, is a < 4 ?

(1) \(10^{(-2a + 2)} < 0.001\)

(2) \(10^{(-2a)} < 0.0001\)

Asked: If a is an integer, is a < 4 ?

(1) \(10^{(-2a + 2)} < 0.001\)
\(10^{(-2a + 2)} < 10^{-3}\)
-2a + 2 < -3
-2a < - 5
a > 2.5
a = {3,4,5,...}
NOT SUFFICIENT

(2) \(10^{(-2a)} < 0.0001\)
\(10^{(-2a)} < 10^{-4}\)
-2a < -4
a > 2
a = {3,4,5,...}
NOT SUFFICIENT

(1) + (2)
(1) \(10^{(-2a + 2)} < 0.001\)
\(10^{(-2a + 2)} < 10^{-3}\)
-2a + 2 < -3
-2a < - 5
a > 2.5
2) \(10^{(-2a)} < 0.0001\)
\(10^{(-2a)} < 10^{-4}\)
-2a < -4
a > 2
a = {3,4,5,...}
NOT SUFFICIENT

IMO E
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