November 17, 2018 November 17, 2018 07:00 AM PST 09:00 AM PST Nov. 17, 7 AM PST. Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT. November 17, 2018 November 17, 2018 09:00 AM PST 11:00 AM PST Join the Quiz Saturday November 17th, 9 AM PST. The Quiz will last approximately 2 hours. Make sure you are on time or you will be at a disadvantage.
Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 31 Jan 2012
Posts: 85

If a, m and n are positive integers, is n^(2a) a multiple of
[#permalink]
Show Tags
Updated on: 30 Apr 2013, 04:40
Question Stats:
52% (01:20) correct 48% (01:29) wrong based on 237 sessions
HideShow timer Statistics
If a, m and n are positive integers, is n^(2a) a multiple of m^a? (1) n is a multiple of m/2 (2) n is a multiple of 2m
Official Answer and Stats are available only to registered users. Register/ Login.
Originally posted by fireinbelly on 30 Apr 2013, 04:33.
Last edited by Bunuel on 30 Apr 2013, 04:40, edited 1 time in total.
Edited the question.




Math Expert
Joined: 02 Sep 2009
Posts: 50608

Re: If a, m and n are positive integers, is n^(2a) a multiple of
[#permalink]
Show Tags
30 Apr 2013, 05:00




Manager
Joined: 26 Feb 2013
Posts: 52
Concentration: Strategy, General Management
WE: Consulting (Telecommunications)

Re: If a, m and n are positive integers, is n^(2a) a multiple of
[#permalink]
Show Tags
30 Apr 2013, 05:21
Option B.
From Stmt 1: n is a multiple of m/2 . case 1:n= 9 , m=6 and a =1 9 is a multiple of 3(m/2) bur 81 is not a multiple of 6.
case 2 : n=8 , m=4 and a=1. 8 is a multiple of 2(m/2) and 8^2 = 64 is a multiple of 4. so insufficient.
stmt 2:
n=2m*k. now both sides raised to the power or 2a gives n^2a = 2^2a * k^2a * m^2a => 2^2a* k^2a * m^a* m^a
Hence it is a multiple of m^a. Sufficient



Intern
Joined: 22 Apr 2014
Posts: 11
Location: India

Re: If a, m and n are positive integers, is n^(2a) a multiple of
[#permalink]
Show Tags
06 Jul 2014, 21:27
The question basically asks if n^2a/m^a =integer,is (n^a.n^a)/m^a =integer,is (n/m)^a.n^a=integer,since n and a are positive integer,it will always be an integer,so the question really is n a multiple of m then only (n/m)^a.n^a=integer
Statement 1 n/(m/2)=integer↪2n/m=integer↪n=1,m=2 then n/m≠integer↪↪but n=2,m=1,then n/m=integer…not sufficient
Statement 2
n/2m=integer↪n/m=2*integer….sufficient
AnswerB



NonHuman User
Joined: 09 Sep 2013
Posts: 8773

Re: If a, m and n are positive integers, is n^(2a) a multiple of
[#permalink]
Show Tags
19 Oct 2018, 05:42
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources




Re: If a, m and n are positive integers, is n^(2a) a multiple of &nbs
[#permalink]
19 Oct 2018, 05:42






