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Bunuel
If a rectangle with length 8 and width x has the same perimeter as a square with side of length 6, what is the value of x?

(A) 2
(B) 4
(C) 7
(D) 10
(E) 16

Length of rectangle = 8
Width of rectangle = x

Perimeter of rectangle = 2(8+x)

Perimeter of square = 4*6

2*(8+x) = 4*6
8+x = 12
x = 4

Answer B
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Bunuel
If a rectangle with length 8 and width x has the same perimeter as a square with side of length 6, what is the value of x?

(A) 2
(B) 4
(C) 7
(D) 10
(E) 16


Hi,
Ofcourse Q has already been answered above in the Correct way, just a fun fact/observation.

The side of square would always be AVERAGE of the two sides of rectangle.

So \(6=\frac{8+x}{2}......12=8+x..........x=4\)
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