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# If a sequence of 8 consecutive even integers

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Senior Manager
Joined: 02 Mar 2017
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If a sequence of 8 consecutive even integers  [#permalink]

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Updated on: 26 Apr 2017, 05:35
00:00

Difficulty:

5% (low)

Question Stats:

86% (01:06) correct 14% (01:22) wrong based on 63 sessions

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If a sequence of 8 consecutive even integers with increasing values has 36 as its eighth term,then the least number in the sequence is

A)50
B)48
C)24
D)22
E)20

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Originally posted by VyshakhR1995 on 26 Apr 2017, 02:57.
Last edited by VyshakhR1995 on 26 Apr 2017, 05:35, edited 1 time in total.
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Re: If a sequence of 8 consecutive even integers  [#permalink]

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26 Apr 2017, 03:36
A
50 48 46 44 42 40 38 36

I m not sure .. in increasing order how 36 can come as 8th term

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Re: If a sequence of 8 consecutive even integers  [#permalink]

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26 Apr 2017, 04:33
Is there a typo in the question

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Posted from my mobile device
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Re: If a sequence of 8 consecutive even integers  [#permalink]

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26 Apr 2017, 05:37
warriorguy wrote:
Is there a typo in the question

Posted from my mobile device

Posted from my mobile device
Manbarasan wrote:
A
50 48 46 44 42 40 38 36

I m not sure .. in increasing order how 36 can come as 8th term

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Sorry guys I typed it wrong---Edited the question
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Re: If a sequence of 8 consecutive even integers  [#permalink]

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26 Apr 2017, 06:45
consecutive even numbers have a common difference of 2
hene nth term(an) = first term(a1) + (n-1)*d( common difference)
36=a1+(8-1)*2
36-14=a1
a1=22
Option D
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Re: If a sequence of 8 consecutive even integers  [#permalink]

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26 Apr 2017, 06:50
Here is how I solved:

8 consecutive even integers. Since we know that 36 is included in the sequence then we need to know the seven previous terms.

2*7 = 14

36-14 = 22
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Re: If a sequence of 8 consecutive even integers  [#permalink]

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26 Apr 2017, 07:22
Concescutive integers follow a pattern of
x, x+k, x+2k,x+3k....
In this case since there are 8 integers, we have to equate the eighth integer to
X+7k=36
Where k=2(since it states even integers)
Therefore x=22 which is your first term
Option D

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If a sequence of 8 consecutive even integers  [#permalink]

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27 Apr 2017, 13:12
A+ (n-1)d= An
A+ (8-1)2=36
A=36-14=22

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Re: If a sequence of 8 consecutive even integers  [#permalink]

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29 Apr 2017, 08:51
VyshakhR1995 wrote:
If a sequence of 8 consecutive even integers with increasing values has 36 as its eighth term,then the least number in the sequence is

A)50
B)48
C)24
D)22
E)20

If we let x = the first term, then x + 2 = second term, x + 4 = third term, x + 6 = fourth term, …, x + 14 = eighth term.

Thus:

x + 14 = 36

x = 22

Therefore, 22 is the least term in the set.

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Re: If a sequence of 8 consecutive even integers &nbs [#permalink] 29 Apr 2017, 08:51
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