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23 Jul 2018, 14:36
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (01:28) correct
15%
(01:29)
wrong
based on 54
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If a solid metal cylinder with radius 3 and height 12 is melted and then formed into a solid sphere, what is the radius of the sphere?
Note: Volume of sphere = (4/3)(π)(radius3)
A) ∛6
B) ∛12
C) ∛36
D) 3
E) 3∛3
Note: Volume of sphere = (4/3)(π)(radius3)
A) ∛6
B) ∛12
C) ∛36
D) 3
E) 3∛3
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23 Jul 2018, 14:58
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E
The new sphere will have the same volume of Cylinder.
So, the volume of sphere= volume of cylinder
(4/3)(π)([radius of sphere]³) = (π)(radius of cylinder ^2)(height)
Solving for the radius of the sphere in the above formula gives answer E.
The new sphere will have the same volume of Cylinder.
So, the volume of sphere= volume of cylinder
(4/3)(π)([radius of sphere]³) = (π)(radius of cylinder ^2)(height)
Solving for the radius of the sphere in the above formula gives answer E.
23 Jul 2018, 15:33
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Equate the formula for volumes for a cylinder to a sphere:
πr^2h = 4/3 π R^3
π will immediately cancel out, and inputting values r=3 and h=12,
3*3*12 =4/3*(R^3)
solve for this to get the answer!
πr^2h = 4/3 π R^3
π will immediately cancel out, and inputting values r=3 and h=12,
3*3*12 =4/3*(R^3)
solve for this to get the answer!
