It is currently 19 Oct 2017, 09:45

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If a square region has area x, what is the length of its diagonal in

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 41893

Kudos [?]: 128871 [0], given: 12183

If a square region has area x, what is the length of its diagonal in [#permalink]

### Show Tags

27 Sep 2017, 04:52
00:00

Difficulty:

(N/A)

Question Stats:

63% (00:35) correct 38% (00:25) wrong based on 15 sessions

### HideShow timer Statistics

If a square region has area x, what is the length of its diagonal in terms of x?

(A) √x
(B) √(2x)
(C) 2√x
(D) x√2
(E) 2x
[Reveal] Spoiler: OA

_________________

Kudos [?]: 128871 [0], given: 12183

Director
Joined: 22 May 2016
Posts: 813

Kudos [?]: 264 [0], given: 551

If a square region has area x, what is the length of its diagonal in [#permalink]

### Show Tags

27 Sep 2017, 05:56
Bunuel wrote:
If a square region has area x, what is the length of its diagonal in terms of x?

(A) √x
(B) √(2x)
(C) 2√x
(D) x√2
(E) 2x

Because $$s^2$$ = area of a square:

$$s^2 = x$$
$$s = \sqrt{x}$$

A square's diagonal* is given by $$s\sqrt{2}$$

$$\sqrt{x} * \sqrt{2} = \sqrt{2x}$$

*OR use Pythagorean theorem, where hypotenuse = diagonal = d

$$(\sqrt{x})^2 + (\sqrt{x})^2 = d^2$$
$$2x = d^2$$
$$\sqrt{2x} = \sqrt{d^2}$$
$$d =\sqrt{2x}$$

Kudos [?]: 264 [0], given: 551

If a square region has area x, what is the length of its diagonal in   [#permalink] 27 Sep 2017, 05:56
Display posts from previous: Sort by