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If abcd ≠ 0, is ab2c3d4 < 0?

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If abcd ≠ 0, is ab2c3d4 < 0?  [#permalink]

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New post 01 Mar 2014, 06:26
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If abcd ≠ 0, is \(ab^2c^3d^4 < 0 ?\)

(1) \(ab^2c^3 < 0\)

(2) \(b^2c^3d^4 < 0\)

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Re: If abcd ≠ 0, is ab2c3d4 < 0?  [#permalink]

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New post 01 Mar 2014, 06:36
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Anshulmodi wrote:
If abcd ≠ 0, is \(ab^2c^3d^4 < 0 ?\)

(1) \(ab^2c^3 < 0\)

(2) \(b^2c^3d^4 < 0\)


If abcd ≠ 0, is \(ab^2c^3d^4 < 0\)?

Is \(ab^2c^3d^4 < 0\)? divide by \(b^2c^2d^4\): is \(ac<0\)?

We can safely reduce by b^2c^2d^4, since this expression will always be positive: the square of a number is always non-negative plus we know that neither of the unknowns is zero, hence b^2c^2d^4>0

(1) \(ab^2c^3 < 0\) --> divide by \(b^2c^2\): \(ac<0\). Sufficient.

(2) \(b^2c^3d^4 < 0\) --> divide by \(b^2c^2d^4\): \(c<0\). We need to know the sign of a. Not sufficient.

Answer: A.
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Re: If abcd ≠ 0, is ab2c3d4 < 0?  [#permalink]

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New post 28 Jul 2018, 09:15
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Re: If abcd ≠ 0, is ab2c3d4 < 0? &nbs [#permalink] 28 Jul 2018, 09:15
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