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03 Dec 2019, 02:28
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If an integer greater than 100 and less than 1,000 is to be selected at random, what is the probability that the integer selected will be a multiple of 7?
A. \(\frac{142}{999}\)
B. \(\frac{142}{900}\)
C. \(\frac{142}{899}\)
D. \(\frac{128}{900}\)
E. \(\frac{128}{899}\)
Are You Up For the Challenge: 700 Level Questions
A. \(\frac{142}{999}\)
B. \(\frac{142}{900}\)
C. \(\frac{142}{899}\)
D. \(\frac{128}{900}\)
E. \(\frac{128}{899}\)
Are You Up For the Challenge: 700 Level Questions
03 Dec 2019, 02:33
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total integers >100 <1000 ; 999-101+1 = 899
and multiples of 7 <100 ; 14 and <1000 ; 142
so 142-14 ; 128 ;
P = 128/899
IMO E
and multiples of 7 <100 ; 14 and <1000 ; 142
so 142-14 ; 128 ;
P = 128/899
IMO E
Bunuel
If an integer greater than 100 and less than 1,000 is to be selected at random, what is the probability that the integer selected will be a multiple of 7?
A. \(\frac{142}{999}\)
B. \(\frac{142}{900}\)
C. \(\frac{142}{899}\)
D. \(\frac{128}{900}\)
E. \(\frac{128}{899}\)
Are You Up For the Challenge: 700 Level Questions
A. \(\frac{142}{999}\)
B. \(\frac{142}{900}\)
C. \(\frac{142}{899}\)
D. \(\frac{128}{900}\)
E. \(\frac{128}{899}\)
Are You Up For the Challenge: 700 Level Questions
04 Dec 2019, 00:32
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The number of integers greater than 100 and less than 1,000
(last integer-first integer)+1
(999-101)+1=899
The number of multiple of 7 integers greater than 100 and less than 1,000
\(\frac{{last integer-first integer}}{7 }\)+1
\(\frac{{994-105}}{7}+1=128\)
\(\frac{128}{899}\)
IMO
Ans: E
(last integer-first integer)+1
(999-101)+1=899
The number of multiple of 7 integers greater than 100 and less than 1,000
\(\frac{{last integer-first integer}}{7 }\)+1
\(\frac{{994-105}}{7}+1=128\)
\(\frac{128}{899}\)
IMO
Ans: E
