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Bunuel
3, 8, a, 17, b

If b = 3a, is the average (arithmetic mean) of the five terms in the list above less than 8?

(1) a > 2
(2) a^2 < 9


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\(\frac{3+8+a+17+3a}{5}<8\)
a<3

(1) a > 2, Insufficient
(2) \(a^2 < 9\) =>\( -3<a<3\) => Sufficient

Ans B
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3, 8, a, 17, b

If b = 3a, is the average (arithmetic mean) of the five terms in the list above less than 8?

\(\frac{(3+8+a+17+b)}{5}\) < 8 or, 28 +4b < 40 or, a <3

Stat1: a > 2; not sufficient
Stat2: a^2 < 9
-3 < a < 3. Sufficient

So, I think B. :)
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before reading the statements, we get

(a+3+17+8+3a)/5 < 8

Solving the above equation:

a<5, which means a must be lesser than 5 for the above inequality to be true.

St.1 a>2
a = 3,4,5,6....10....20

a is both lesser and greater than 5. Thereby the statement is insufficient.

St.2 a^2 <9

|a| < 3
-3<a<3
Thereby the statement is sufficient.

ANS B
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