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If c≠0 and (a*b)/c < 0, is a/c < 0
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Updated on: 11 Aug 2015, 02:26
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If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ? (1) a < 0 (2) b < 0
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Originally posted by Mascarfi on 10 Aug 2015, 17:58.
Last edited by Bunuel on 11 Aug 2015, 02:26, edited 1 time in total.
Renamed the topic and edited the question.



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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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10 Aug 2015, 18:15
Mascarfi wrote: If c≠0 and \(\frac{(a*b)}{c}\)<0, is \(\frac{a}{c}\)<0 ?
(1) a<0
(2) b<0 \(\frac{ab}{c} < 0\) > 2 cases possible: 1. Either a/c < 0 and b>0 or 2. a/c>0 ad b<0 Per statement 1, a<0 > clearly not sufficient. Per statement 2, b<0> this eliminates case (1) mentioned above leaving just 1 possible case and is thus sufficient. B is the correct answer.



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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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11 Aug 2015, 03:03
Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 Given: \(\frac{(a*b)}{c}<0\) Is \(\frac{a}{c}<0\), to rephrase the qn, is b>0? St 1: a < 0. No info about b. Not Sufficient. St 2: b < 0, which implies that \(\frac{a}{c}>0\). The answer is No. Sufficient. Option B  Pls give kudos if you like this post.



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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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11 Aug 2015, 23:37
Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 Ans: B solution: we have (a*b)/c < 0 ; is a/c<0 means we need to find that a and c have different signs. from the given statement we know that either one or all of them are<0 only then (a*b)/c < 0 will be true. 1) a<0, but it does not say anything about b and c, so what if b and c both <0 ; (a*b)/c < 0 true and a/c>0 what if b and c both >0 ; (a*b)/c < 0 true, and a/c<0 [Insufficient] 2) b<0, no information is given about a and c. so (a*b)/c < 0 to be true either a and c must have the same sign. and in both the cases a/c>0 [Sufficient]
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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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04 Dec 2016, 00:09
Not taken much time to solve this question, Option 1: If a<0, No information about b and c values. Hence, a/c value can not be determined. Insufficient. Option 2: If b<0, To comply the original question, (a∗b)/c<0. The ratio a/c must have to be positive. Hence sufficient. B is the correct answer.



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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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13 Jun 2019, 05:21
Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 chetan2u, could you please help ? Confusion with B, If a =1, b=1, and C=1, then \(\frac{(1*1)}{1}<0\). Therefore, for \(\frac{a}{c}<0\) ; \(\frac{1}{1}<0\) = Ans is No. If a=1, b=2, and C=2, then \(\frac{(1*2)}{2}<0\). Therefore, \(\frac{a}{c}<0\) ; \(\frac{1}{2}<0\) = Ans is Yes. So, how is B okay for the answer.



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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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13 Jun 2019, 05:50
MBA20 wrote: Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 chetan2u, could you please help ? Confusion with B, If a =1, b=1, and C=1, then \(\frac{(1*1)}{1}<0\). Therefore, for \(\frac{a}{c}<0\) ; \(\frac{1}{1}<0\) = Ans is No. If a=1, b=2, and C=2, then \(\frac{(1*2)}{2}<0\). Therefore, \(\frac{a}{c}<0\) ; \(\frac{1}{2}<0\) = Ans is Yes. So, how is B okay for the answer. Hi, If you have 3 variables a,b and c, the relation can be found as far as the sign is concerned.. (a*b)/c<0 means 1) all three are negative so a/c is positive. 2) only one is negative, if any of a and c are negative a/c<0, but if b<0, a/c>0. Now statement II says that b<0, so a and c both can be positive or both can be negative . In both cases a/c>0. So B is sufficient
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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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13 Jun 2019, 06:03
chetan2u wrote: MBA20 wrote: Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 chetan2u, could you please help ? Confusion with B, If a =1, b=1, and C=1, then \(\frac{(1*1)}{1}<0\). Therefore, for \(\frac{a}{c}<0\) ; \(\frac{1}{1}<0\) = Ans is No. If a=1, b=2, and C=2, then \(\frac{(1*2)}{2}<0\). Therefore, \(\frac{a}{c}<0\) ; \(\frac{1}{2}<0\) = Ans is Yes. So, how is B okay for the answer. Hi, If you have 3 variables a,b and c, the relation can be found as far as the sign is concerned.. (a*b)/c<0 means 1) all three are negative so a/c is positive. 2) only one is negative, if any of a and c are negative a/c<0, but if b<0, a/c>0. Now statement II says that b<0, so a and c both can be positive or both can be negative . In both cases a/c>0. So B is sufficient So is it that my assumption value of a,b, and c are wrong. As as per assumption it is fulfilling the condition that " a and c both can be positive or both can be negative" .



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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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13 Jun 2019, 06:07
MBA20 wrote: Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 chetan2u, could you please help ? Confusion with B, If a =1, b=1, and C=1, then \(\frac{(1*1)}{1}<0\). Therefore, for \(\frac{a}{c}<0\) ; \(\frac{1}{1}<0\) = Ans is No. If a=1, b=2, and C=2, then \(\frac{(1*2)}{2}<0\). Therefore, \(\frac{a}{c}<0\) ; \(\frac{1}{2}<0\) = Ans is Yes. So, how is B okay for the answer. I'm your assumptions.. 1/1<0...NO 1/2<0...NO Both times you get a NO... It seems you are reading 1/2 <0 as 1/2<1..
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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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13 Jun 2019, 21:37
Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 #1 a<0 so either b& c are both ve or both +ve so a/c not sufficient to say is <0 #2 b<0 , a & c can be both +ve or ve and a/b >0 sufficient IMO B
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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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13 Jun 2019, 22:01
Hi chetan2u what if in S2 a=0, the S2 is not sufficient as we do not have any info on the nature of a,b chetan2u wrote: MBA20 wrote: Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 chetan2u, could you please help ? Confusion with B, If a =1, b=1, and C=1, then \(\frac{(1*1)}{1}<0\). Therefore, for \(\frac{a}{c}<0\) ; \(\frac{1}{1}<0\) = Ans is No. If a=1, b=2, and C=2, then \(\frac{(1*2)}{2}<0\). Therefore, \(\frac{a}{c}<0\) ; \(\frac{1}{2}<0\) = Ans is Yes. So, how is B okay for the answer. Hi, If you have 3 variables a,b and c, the relation can be found as far as the sign is concerned.. (a*b)/c<0 means 1) all three are negative so a/c is positive. 2) only one is negative, if any of a and c are negative a/c<0, but if b<0, a/c>0. Now statement II says that b<0, so a and c both can be positive or both can be negative . In both cases a/c>0. So B is sufficient
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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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13 Jun 2019, 22:30
Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 Given \(\frac{(a*b)}{c}<0\) > 2 cases are possible Case 1) 1 ve and 2 +ve or Case 2) all 3 ve
\(\frac{a}{c}<0\) ? (1) a < 0 If a < 0 > Case 1) b > 0 & c > 0 > a/c < 0  YES or Case 2) b < 0 & c < 0 > a/c > 0  NO No Definite Answer  Insufficient(2) b < 0 If b < 0 > Case 1) a > 0 & c > 0 > a/c > 0  NO Case 2) a < 0 & c < 0 > a/c > 0  NO A Definite Answer  SufficientIMO Option B Pls Hit Kudos if you like the solution



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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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14 Jun 2019, 00:08
LoneSurvivor wrote: Hi chetan2u what if in S2 a=0, the S2 is not sufficient as we do not have any info on the nature of a,b chetan2u wrote: Mascarfi wrote: If c ≠ 0 and \(\frac{(a*b)}{c}<0\), is \(\frac{a}{c}<0\) ?
(1) a < 0
(2) b < 0 chetan2u, could you please help ? Confusion with B, Hi, If you have 3 variables a,b and c, the relation can be found as far as the sign is concerned.. (a*b)/c<0 means 1) all three are negative so a/c is positive. 2) only one is negative, if any of a and c are negative a/c<0, but if b<0, a/c>0. Now statement II says that b<0, so a and c both can be positive or both can be negative . In both cases a/c>0. So B is sufficient it is given \(\frac{(a*b)}{c}<0\), so none of the three a, b and c will be 0...
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Re: If c≠0 and (a*b)/c < 0, is a/c < 0
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