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\([z^2] = 2\) means that

\(1<z^2\leq{2}\)

Now, Taking Square Root of both the sides.

If Z is positive, then

\(1<z\leq{\sqrt{2}}\)

then [z] = 2

If Z is negative, then

\(-1>z\geq{-\sqrt{2}}\)

then [z] = -1

Answer is A. I only
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itisSheldon
If [z] denotes the least integer greater than or equal to z and [z^2] = 2, which of the following could be the value of [z]?

I. 2
II. 1
III. -2

(A) I only

(B) II only

(C) III only

(D) I and II only

(E) II and III only


Good question...
if [z^2] =2, \(z^2\) lies between 2 and 3
therefore z lies between \(\sqrt{2}=1.4\) and \(\sqrt{3}=1.7\) or between \(-\sqrt{2}=-1.4\) and \(-\sqrt{3}=-1.7\) if z is negative..
so when z is positive it lies between 1.4 and 1.7 and the NEXT greater integer is 2 so [z]=2
but when z is negative it lies between -1.4 and -1.7 and the NEXT greater integer is -1 so [z]=-1.. Be careful here and do not take -2

Only 2 is given
ans A
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I don't understand, where does the z > 1 and z < -1 come from?
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Is my reasoning correct:

We know that [z] will take any number, (ex 1.4), and will round it up to the next highest integer, (2 in the case of 1.4) unless Z is already an integer.

Therefore, as others mentioned,

1<z^2 ≤ 2

Which means that √(Z^2), or Z is either larger than √1, which si 1 or -1, or smaller than √2 or -√2 (1.4, or -1.4)

-1 (or 1) <Z ≤ 1.4 ( or -1.4).

The different possibilities for [Z] are thus

1) 0, because if Z> -1 , the closest higher integer is 0,
2) 2, because if Z>1, Z < 1.4 , the closest integers are 2,
3) -1, because if Z> -1.4, the closest highest integer is -1.

The only option that appears in the answer choices is 2, thus the answer is A.
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I: If z = 1,2 --> [z] = 2 --> [z^2] = 2

II: If z = 0,5 --> [z] = 1 --> [z^2] = 1

III: If z = -2,2 --> [z] = -2 --> [z^2] = 4

Only I works.
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Nice question. Might be good to not follow a heavy paper/pad approach with this one.
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EgmatQuantExpert
If [z] denotes the least integer greater than or equal to z and [\(z^2\)] = 2, which of the following could be the value of [z]?

    I. 2
    II. 1
    III. -2


let us assume z^2 = 1.96 then z= 1.4 and greatest integer function will lead to z= 2

now alternatively in the neagtive axis z^2 =1.96 and z=-1.4 then the greatest integer will be -1 ...........a

and we can safely eleminate the other 2 option with the reasoning at a

therefore IMO a
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If [z] denotes the least integer greater than or equal to z and [\(z^2\)] = 2, which of the following could be the value of [z]?

[\(z^2\)] = 2
1.00000...1<z^2 < 1.99.....9
1.00000....1 < z < 1.34
-1.34 < z < -1

I. 2: z = 1.1; [z] = 2
II. 1: No value of z can be found
III. -2: No value of z can be found

IMO A
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The first line gives us the definition that [Z]>=Z, where [Z] has an integer value but Z can be an integer or non integer value which means that lets suppose Z= 2.1 then [z] is next integer value greater than or equal to Z which will be 3, and if z=2.9 then also [z] will be 3, [z]can't be 2 as per the definition. And the range of values will be 2<[z]<=3

The next statement says that [z^2]=2. Now as per above we know that z will be less than equal to 2 and greater than 1, z can be negative or positive because of square of variable. Now as per example given we can write [z^2] range as 1<[z^2]<=2

So it follows two inequality z^2>1 and z^2<=2

When we solve this we will get intervals, we can't take negative intervals for the values of [z^2] because of definition given because if take z as -1.41 then next integer value will be -1 which doesn't satisfy the condition given. Hence for positive z can take only values for 1<z<=sqrt2.

Now check for any value of this intervals of z=1.2, z^2= 1.44 hence as per question [z^2]=2 satisfied

EgmatQuantExpert
If [z] denotes the least integer greater than or equal to z and [\(z^2\)] = 2, which of the following could be the value of [z]?

    I. 2
    II. 1
    III. -2


Answer Choices



    A. I only
    B. II only
    C. III only
    D. I and II only
    E. II and III only
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