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If each possible product is between 15 and 200, then the least and gre
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CrackverbalGMAT
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Joined: 03 Oct 2013
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Re: If each possible product is between 15 and 200, then the least and gre [#permalink] New post  18 Jun 2021, 03:20
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Solution:

Let the first card drawn has n written in it and the next which is larger is n+1 with the product as n(n+1)

=>15<n(n+1)<200

Using the options-

A- If n = 3 then n(n+1) = 3*4=12 and 12<15 -Eliminate A and B with the same logic

C- If n=4, then n(n+1)=20 and 20>15 => The least value for n has to be 4 and not 5-Eliminate D and hold on to C

D-If n=14 then n(n+1) = 14*15 = 210 > 200(maximum value permitted) -Eliminate D-

(option c)

Devmitra Sen
GMAT SME
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NamaySharma
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Joined: 21 Mar 2021
Posts: 13
Re: If each possible product is between 15 and 200, then the least and gre [#permalink] New post  10 Oct 2021, 17:34
Spunkerspawn wrote:
I found the wording a bit confusing, the child draws a card and multiplies it with the next large integer.

I didn't really get the idea that the card numbers were consecutive.

Agreed. Had the same issue.
GMAT Club Bot
gmatclubot
Re: If each possible product is between 15 and 200, then the least and gre [#permalink]
10 Oct 2021, 17:34
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