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# If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?

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Math Expert
Joined: 02 Sep 2009
Posts: 48037
If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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27 Jul 2018, 01:11
00:00

Difficulty:

25% (medium)

Question Stats:

95% (00:15) correct 5% (00:16) wrong based on 111 sessions

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If $$f(x) = x^2 + 1$$, what is the value of $$f(2) + f(-2)$$?

(A) 0
(B) 1
(C) 4
(D) 5
(E) 10

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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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27 Jul 2018, 01:15
f(x) = $$x^2 + 1$$

=> f(2) = $$2^2 + 1$$ = 4 + 1 = 5

=> f(-2) = $$(-2)^2 + 1$$ = 4 + 1 = 5

f(2) + f(-2) = 5 + 5 = 10

Hence option E
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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27 Jul 2018, 02:13
f(x) = x^2 + 1

f(2) + f(−2)
= ( 2^2 + 1 ) + ( (-2)^2 + 1 )
= 5 + 5
= 10

Hence, E.
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Joined: 24 Dec 2017
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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27 Jul 2018, 05:06
f(X) = x^2+1
f(2) = 2^2+1 = 5
f(-2) = -2^2+1 = 5
Therefore f(2) + f(-2) = 10

IMO E
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Joined: 04 Jul 2018
Posts: 5
Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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07 Aug 2018, 13:26
1
Hi,
Can somebody explain why is B instead of E???
Math Expert
Joined: 02 Sep 2009
Posts: 48037
Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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08 Aug 2018, 03:32
MartaR wrote:
Hi,
Can somebody explain why is B instead of E???

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It's E. Edited. Thank you.
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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09 Aug 2018, 03:57
Just put the values into x and will get 4+1+4+1=10
Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)? &nbs [#permalink] 09 Aug 2018, 03:57
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