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If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?

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Math Expert
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Joined: 02 Sep 2009
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If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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New post 27 Jul 2018, 01:11
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

97% (00:22) correct 3% (00:27) wrong based on 131 sessions

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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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New post 27 Jul 2018, 01:15
f(x) = \(x^2 + 1\)

=> f(2) = \(2^2 + 1\) = 4 + 1 = 5

=> f(-2) = \((-2)^2 + 1\) = 4 + 1 = 5

f(2) + f(-2) = 5 + 5 = 10

Hence option E
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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New post 27 Jul 2018, 02:13
f(x) = x^2 + 1

f(2) + f(−2)
= ( 2^2 + 1 ) + ( (-2)^2 + 1 )
= 5 + 5
= 10

Hence, E.
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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New post 27 Jul 2018, 05:06
f(X) = x^2+1
f(2) = 2^2+1 = 5
f(-2) = -2^2+1 = 5
Therefore f(2) + f(-2) = 10

IMO E
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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New post 07 Aug 2018, 13:26
1
Hi,
Can somebody explain why is B instead of E???
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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New post 08 Aug 2018, 03:32
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?  [#permalink]

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New post 09 Aug 2018, 03:57
Just put the values into x and will get 4+1+4+1=10
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Re: If f(x) = x^2 + 1, what is the value of f(2) + f(–2)?   [#permalink] 09 Aug 2018, 03:57
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