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31 Dec 2010, 03:12
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
68% (01:15) correct
32%
(01:08)
wrong
based on 817
sessions
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If he did not stop along the way, what speed did Bill average on his 3-hour trip?
(1) He traveled a total of 120 miles.
(2) He traveled half the distance at 30 miles per hour, and half the distance at 60 miles per hour.
(1) He traveled a total of 120 miles.
(2) He traveled half the distance at 30 miles per hour, and half the distance at 60 miles per hour.
If he did not stop along the way, what speed did Bill average on his 3-hour trip?
(1) He travelled a total of 120 miles.
(2) He travelled half the distance at 30 miles per hour and half the distance at 60 miles per hour.
The answer is D But the explanation at the end of the test doesn't seem to take into account the fact that Bill stopped along the way and that time has to be excluded.
Can someone shed some light on this please?
(1) He travelled a total of 120 miles.
(2) He travelled half the distance at 30 miles per hour and half the distance at 60 miles per hour.
The answer is D But the explanation at the end of the test doesn't seem to take into account the fact that Bill stopped along the way and that time has to be excluded.
Can someone shed some light on this please?
31 Dec 2010, 03:33
Kudos
Bookmarks
HygeinicGangster
Welcome to Gmat Club!
Can you please post PS questions in the PS subforum: gmat-problem-solving-ps-140/ and DS questions in the DS subforum: gmat-data-sufficiency-ds-141/ No posting of PS/DS questions is allowed in the main Math forum. Thanks.
As for you question.
If he did not stop along the way, what speed did Bill average on his 3-hour trip?
The stem explicitly states that Bill did not stop along the way, so your doubt is not valid.
(1) He travelled a total of 120 miles --> (average speed) = (total distance traveled) / (time spent) --> (average speed) = 120/3 = 40 miles per hour. Sufficient.
(2) He travelled half the distance at 30 miles per hour and half the distance at 60 miles per hour --> (d/2)/30+(d/2)/60=3 (the time spent for the first half of the distance would be (distance traveled) / (speed)=(d/2)/30 and the time spent for the second half of the distance would be (distance traveled) / (speed)=(d/2)/60)). Solving (d/2)/30+(d/2)/60=3 for d: d=120 miles --> (average speed) = 120/3 = 40 miles per hour. Sufficient.
Or: as he traveled d/2 mile at 30 miles per hour and then the same distance of d/2 at 30*3=60 miles per hour (twice the previous speed) then he must have spent twice as much time for the first half as for the second (t1/t2=2/1), so as he spent total of 3 hours on the entire trip then he must have spent 2 hours for the first half and 1 hour for the second: d=2*30+1*60=120 --> (average speed) = 120/3 = 40 miles per hour. Sufficient.
Answer: D.
Hope it's clear.
31 Dec 2010, 03:57
Kudos
Bookmarks
Oh should have looked closer for PS sub-forum.
Thanks for clarification! Bill didn't stop. And I was thinking that Bill stopped but we have to solve by excluding the time that he stopped. Wow.
Thanks for clarification! Bill didn't stop. And I was thinking that Bill stopped but we have to solve by excluding the time that he stopped. Wow.
