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# If I walk at 4 km/hr, I miss the bus by 10 minutes. If I walk at 5 km/

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Joined: 02 Sep 2009
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If I walk at 4 km/hr, I miss the bus by 10 minutes. If I walk at 5 km/  [#permalink]

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29 Jan 2019, 03:23
1
1
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Difficulty:

55% (hard)

Question Stats:

50% (02:36) correct 50% (02:41) wrong based on 24 sessions

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If I walk at 4 km/hr, I miss the bus by 10 minutes. If I walk at 5 km/hr, I reach 5 minutes before the arrival of the bus. How far should I walk to reach the bus stand?

(A) 5 km
(B) 10 km
(C) 15 km
(D) 20 km
(E) 25 km

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Re: If I walk at 4 km/hr, I miss the bus by 10 minutes. If I walk at 5 km/  [#permalink]

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29 Jan 2019, 03:41
Bunuel wrote:
If I walk at 4 km/hr, I miss the bus by 10 minutes. If I walk at 5 km/hr, I reach 5 minutes before the arrival of the bus. How far should I walk to reach the bus stand?

(A) 5 km
(B) 10 km
(C) 15 km
(D) 20 km
(E) 25 km

Distance = Speed * Time

Let, Normal Speed = S km/hr
Normal Time = T minutes

now, Distance = S*T = 4*(T+10) = 5*(T-5)

i.e. (T+10)/(T-5) = 5/4

i.e. 4T + 40 = 5T - 25

i.e. T = 65 minutes

i.e. Distance = 5*(T-5) = 5*(65-50)/60 = 5 km . (converting minutes into hour by dividing (65-5) by 60)

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Re: If I walk at 4 km/hr, I miss the bus by 10 minutes. If I walk at 5 km/  [#permalink]

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29 Jan 2019, 04:08
Bunuel wrote:
If I walk at 4 km/hr, I miss the bus by 10 minutes. If I walk at 5 km/hr, I reach 5 minutes before the arrival of the bus. How far should I walk to reach the bus stand?

(A) 5 km
(B) 10 km
(C) 15 km
(D) 20 km
(E) 25 km

we can solve this considering relation that distance to bus stand is same at both times
so
speed = s kmph and time = t
4*(t+10)=5*(t-5)
t+10/t+5=5/4
solve for t = 65 mins ; 65/60 hrs

distance = 4 * (t+10) = 4* 75 /60 = 5 kms
IMO A
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Re: If I walk at 4 km/hr, I miss the bus by 10 minutes. If I walk at 5 km/   [#permalink] 29 Jan 2019, 04:08
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