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If it would take one machine 10 minutes to fill a large production ord

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If it would take one machine 10 minutes to fill a large production ord [#permalink]

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New post 24 Nov 2015, 09:49
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Question Stats:

82% (00:54) correct 18% (00:56) wrong based on 88 sessions

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If it would take one machine 10 minutes to fill a large production order and another machine 12 minutes to fill the same order, how many minutes would it take both machines working together, at their respective rates, to fill the order?

A. 4 1/60
B. 5
C. 5 5/11
D. 5 1/2
E. 11
[Reveal] Spoiler: OA

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Re: If it would take one machine 10 minutes to fill a large production ord [#permalink]

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New post 24 Nov 2015, 10:16
Bunuel wrote:
If it would take one machine 10 minutes to fill a large production order and another machine 12 minutes to fill the same order, how many minutes would it take both machines working together, at their respective rates, to fill the order?

A. 4 1/60
B. 5
C. 5 5/11
D. 5 1/2
E. 11


C
the total rate : 1/10 + 1/12 = 11/60
Work/Rate = 1*60/11 or 5 5/11
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If it would take one machine 10 minutes to fill a large production ord [#permalink]

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New post 24 Nov 2015, 10:26
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Bunuel wrote:
If it would take one machine 10 minutes to fill a large production order and another machine 12 minutes to fill the same order, how many minutes would it take both machines working together, at their respective rates, to fill the order?

A. 4 1/60
B. 5
C. 5 5/11
D. 5 1/2
E. 11


Let the total production order be of 60 units

\(1^{st}\) machine can fill the production order at 6 units per minute

\(2^{nd}\) machine can fill the production order at 5 units per minute

So, \(1^{st}\) and \(2^{nd}\) machine working togather can fill the production order at 11 units per minute

The total production order is of 60 units so the time taken to complete the order is - \(\frac{60}{5}\) = \(5 \frac{5}{11}\) minutes

Hence answer is (C) , \(5 \frac{5}{11}\) minutes
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Re: If it would take one machine 10 minutes to fill a large production ord [#permalink]

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New post 24 Nov 2015, 10:32
Since , Machine 1-M1 take 10 mins to fill the order
The work done by M1 in a min = 1/10
Machine 2- M2 take 12 mins to fill the same order
and work done by M2 in a min = 1/12

Total work done by M1 and M2 in a min = 1/10 + 1/12 = 11/60
Time needed for M1 and M2 to complete the order = 60/11 = 5 5/11

Answer C
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Re: If it would take one machine 10 minutes to fill a large production ord [#permalink]

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New post 24 Nov 2015, 23:39
Hi All,

This question can be solved using the Work Formula:

Work = (A)(B)/(A+B) where A and B are the individual completion rates of the respective entities (for the same job).

We're told that one machine takes 10 minutes to complete a job and another machine takes 12 minutes to complete the same job. Plugging in those values gets us...

(10)(12)/(10+12) = 120/22 = 5 10/22 = 5 5/11 minutes

Final Answer:
[Reveal] Spoiler:
C


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Re: If it would take one machine 10 minutes to fill a large production ord [#permalink]

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Re: If it would take one machine 10 minutes to fill a large production ord   [#permalink] 19 Dec 2017, 05:12
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