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Bunuel
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consider the amount of money with Doug be $x
it is given Josh has \(\frac{3}{4}\) th amount of what Doug has , so Josh has \(\frac{3}{4}\) x

it is also given that amount with Josh is 3 times the amount with Brad
so Brad has (\(\frac{3x}{4}\))/3 = $ x/4

\(\frac{3x}{4}\) +\(\frac{x}{4}\) + x = 72

solving we get x = 36
so the amount with Doug is $ 36
correct answer - E
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J + D + B = 72 (equation 1)
J = 3B (equation 2)
J = (3/4)D (equation 3)

Since we are looking for variable D, it will be faster to convert J and B in equation 1 to their equivalent amount in variable D.

We already know that J = (3/4)D and now just have to figure out B's equivalent in variable D.

Combining equations 2 and 3, we know that 3B = (3/4)D, hence B = (1/4)D (equation 4).

Substituting equation 2 and equation 4 into equation 1 gives us: (3/4)D + D + (1/4)D = 72.
Simplifying that gives us 2D = 72.
Hence, D = 36 (answer E)
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Bunuel
If Josh, Doug, and Brad have a total of $72 between them, and Josh has three times as much money as Brad but only three-fourths as much as Doug, how much money does Doug have?

A. $8
B. $9
C. $27
D. $32
E. $36
I used Brad, B, as the "base." This answer looks time-consuming. It isn't; I just laid out the steps.

\(B + J + D = 72\)

\(J = 3B\)

\(J = \frac{3}{4}D\)

\(\frac{4}{3}J =\\
(\frac{3}{4})*(\frac{4}{3})D\)

\(D =\\
\frac{4}{3}J\)

Substitute \(J = 3B\)
\(D= \frac{4}{3}*(3B) = 4B\)

\(B + 3B + 4B = 72\)
\(8B = 72\)
\(B = 9\)

\(D = 4B\)
\(D = 36\)


Answer E
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Bunuel
If Josh, Doug, and Brad have a total of $72 between them, and Josh has three times as much money as Brad but only three-fourths as much as Doug, how much money does Doug have?

A. $8
B. $9
C. $27
D. $32
E. $36

J + D + B = 72

J = 3B & J =3/4 D...(This means that Doug's amount is great....so I think in choices C, D & E)

Pick choice D ( strategy between 2 answers) ...So we do not do many calculation

Doug =32

J = 3/4 * 32 = 24

B = 8

32 + 24 + 8 = 64..it means Doug has more than 32...........So we have only one answer left & no need to check

Answer: E
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Bunuel
If Josh, Doug, and Brad have a total of $72 between them, and Josh has three times as much money as Brad but only three-fourths as much as Doug, how much money does Doug have?

A. $8
B. $9
C. $27
D. $32
E. $36

Solution:

We can create the equations:

J + D + B = 72

and

J = 3B

J/3 = B

and

J = 3D/4

4J/3 = D

Substituting, we have:

J + 4J/3 + J/3 = 72

Multiplying by 3, we have:

3J + 4J + J = 216

8J = 216

J = 27

Thus D = 4(27)/3 = 36.

Answer: E

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Bunuel
If Josh, Doug, and Brad have a total of $72 between them, and Josh has three times as much money as Brad but only three-fourths as much as Doug, how much money does Doug have?

A. $8
B. $9
C. $27
D. $32
E. $36
Let B = 3 , J = 9 and D = 12

Thus, 24 represents 72
Or, 1 represents 3
And 12 represents 36 , Answer must be (E)
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If Josh, Doug, and Brad have a total of $72 between them, and Josh has three times as much money as Brad but only three-fourths as much as Doug, how much money does Doug have?

Total = 72

Lets consider money that Brad has = x

so josh has 3x

josh has $3x which is three-fourth as much as Doug, so doug has $4x

x+3x+4x=72
8x=72
x=9

Doug has $4x
substituting value of x , we get 4x = 4*9 = 36

Doug has $36

Ans: E
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J + B + D = 72

J = 3B

J = 3D/4

3B + B + 4J/3 = 72 ---> 3B + B + 4B = 72 ---> B = 9

J = 3 x 9 = 27 = 3D / 4

D = 36

Answer is E.
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If Josh, Doug, and Brad have a total of $72 between them, and Josh has three times as much money as Brad but only three-fourths as much as Doug, how much money does Doug have?

A. $8
B. $9
C. $27
D. $32
E. $36

J : B = 3 : 1
J : D = \(3/4\) : 1 ( Josh has three times as much money as Brad but only three-fourths as much as Doug)
(Multiply both sides by 4) J : D = 3 : 4
Combining ratios \(J/B\) = \(3/1\), \(J/D\) = \(3/4\)
J : B : D = 3 : 1 : 4
Therefore Doug's share = 4/8 * 72 = $36
E
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