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# If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe

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Manager
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If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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Updated on: 04 Oct 2013, 00:01
2
00:00

Difficulty:

25% (medium)

Question Stats:

76% (01:47) correct 24% (02:23) wrong based on 184 sessions

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If k > 0, x + k = y, and y + 3k = z, what is the ratio between z - x and y - x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1

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Originally posted by manishuol on 14 May 2013, 21:44.
Last edited by Bunuel on 04 Oct 2013, 00:01, edited 1 time in total.
Edited the question.
Intern
Joined: 14 May 2013
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Concentration: Entrepreneurship, General Management
Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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14 May 2013, 21:54
manishuol wrote:
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1

The question is not clear, all I can see is a question mark:
z � x and y � x

Can you repost this?
Or is this z?x and y?x the actual question?
Manager
Status: Pushing Hard
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Location: India
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GPA: 3.33
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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14 May 2013, 23:23
psychout wrote:
manishuol wrote:
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1

The question is not clear, all I can see is a question mark:
z � x and y � x

Can you repost this?
Or is this z?x and y?x the actual question?

This is How the Question is ............
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If you don’t make mistakes, you’re not working hard. And Now that’s a Huge mistake.
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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15 May 2013, 01:29
manishuol wrote:
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1

Hi,

From the answer, I could only assume that "z � x" is z-x.
So, (z-x)/(y-x) = 4k/k = 4:1
thus (E)

Regards,
Intern
Joined: 02 Jul 2013
Posts: 6
Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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02 Oct 2013, 12:07
1
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1

Picking numbers is probably the fastest solution to solve this problem. First, k>0 = k could be ANY positive number. For the purposes of the explanation K= 2. x + 2 = y and y + 3(2) = z. Rearrange the latter equation as to isolate y.

X + 2 = Y
Z - 6 = Y

Now pick Any number for Y. For the sake of our example Y will be 10. Now the equation looks like:

X + 2 = 10
Z - 6 = 10

Solve for X. Solve for Z. X= 8 and Z = 16

what is the ratio between z � x and y � x
16 to 8 as 10 to 8
8 2
8/2 = 4 2/2=1

Thus answer choice E is correct- 4 to 1.
Intern
Joined: 06 Feb 2013
Posts: 21
Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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03 Oct 2013, 21:11
cmclaurin wrote:

what is the ratio between z � x and y � x
16 to 8 as 10 to 8
8 2
8/2 = 4 2/2=1

Thus answer choice E is correct- 4 to 1.

Could you please elaborate on how you got 8 2 and further?
thanks
Intern
Joined: 02 Jul 2013
Posts: 6
Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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03 Oct 2013, 21:27
16 - 8 = 8

10 - 8 = 2

I hope this is helpful now. Lol (I'm being a troll). Thanks
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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03 Oct 2013, 23:51
manishuol wrote:
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1

Assuming that the required ratio is (z - x)/(y - x),

x + k = y
y - x = k

y + 3k = z
x + k + 3k = z
z - x = 4k

(z - x)/(y - x) = 4/1
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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04 Oct 2013, 23:31
(z-x )/ (y-x) == (y + 3k -x )/ (y-x) where k = y-x

hence == (y-x) + 3(y-x) / ( y-x) = 4(y-x)/(y-x) == 4/1 !!
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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04 Mar 2015, 17:49
Hi All,

This question is perfect for TESTing VALUES.

We're given 3 "rules" that we have to follow (regarding the values we choose to TEST):
1) K > 0
2) X + K = Y
3) Y + 3K = Z

Let's keep the values small:
X = 1
K = 2
1 + 2 = 3 = Y

3 + 3(2) = 9 = Z

The question asks for the ratio of (Z-X) to (Y-X). Using the values we chose....

(9-1) to (3-1) = 8 to 2 = 4 to 1

GMAT assassins aren't born, they're made,
Rich
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe  [#permalink]

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14 Jan 2018, 10:29
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe   [#permalink] 14 Jan 2018, 10:29
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