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Dang, Bunnuel. I'm about to just study your explanations for the quant section of the GMAT. lol What was your undergrad degree in? GMAT math? I'm jk. Thanks for your help
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ykaiim
If K is a positive integer, how many different prime numbers are factors of the expression \(K^2\)?

1) Three different prime numbers are factors of \(4K^4\).
2) Three different prime numbers are factors of 4K.

Combining is insufficient:

If k = 4 then there is only one prime number in 4K or 4K^2
If k = 5 then there are two prime numbers in 4K or 4K^2
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Bunuel
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If K is a positive integer, how many different prime numbers are factors of the expression \(K^2\)?

1) Three different prime numbers are factors of \(4K^4\).
2) Three different prime numbers are factors of 4K.

First of all \(k^x\) (where \(x\) is an integer \(\geq{1}\)) will have as many different prime factors as integer \(k\). Exponentiation doesn't "produce" primes.

Next: \(p^y*k^x\) (where \(p\) is a prime and \(y\) is an integer \(\geq{1}\)) will have as many different prime factors as integer \(k\) if \(k\) already has \(p\) as a factor OR one more factor than \(k\)if \(k\) doesn't have \(p\) as a factor .

So, the question basically is: how many different prime numbers are factors of \(k\)?

(1) Three different prime numbers are factors of \(4k^4\) --> if \(k\) itself has 2 as a factor (eg 30) than it's total # of primes is 3 but if k doesn't have 2 as a factor (eg 15) than it's total # of primes is 2. Not sufficient.

(2) Three different prime numbers are factors of \(4k\) --> the same as above: if \(k\) itself has 2 as a factor (eg 30) than it's total # of primes is 3 but if k doesn't have 2 as a factor (eg 15) than it's total # of primes is 2. Not sufficient.

(1)+(2) Nothing new, k can be 30 (or any other number with 3 different primes, out of which one factor is 2) than the answer is 3 or k can be 15 (or any other number with 2 different primes, out of which no factor is 2) than the answer is 2. Not sufficient.

Answer: E.

Another method that worked for me was to find integer K-if we find K we can find its factors.
Both statements have 4 as a multiplier which is not divisible by any of the prime factors on the LHS. Hence K cannot be found as an integer so E. Bunuel, does this logic make sense? Please enlighten!
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Tricky question. But it is E as there is no way to know whether 2 was a factor in K or not. Neither solution alone gives a direct hint to this, and together it can't be solved either.
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ykaiim
If K is a positive integer, how many different prime numbers are factors of the expression \(K^2\)?

1) Three different prime numbers are factors of \(4K^4\).
2) Three different prime numbers are factors of 4K.

K>0
K will have the same number of prime factors as \(K^2\)
So the question is asking for the number of prime factors of K.

1) 4\(K^4\) = \(P^a\)*\(Q^b\)*\(R^c\)
If K = 15, then 4\(K^4\) has 3 factors i.e. 2,3,5 and K has 2 factors i.e. 3 and 5.
If K = 30, then 4\(K^4\) has 3 factors i.e. 2,3,5 BUT K has 3 factors i.e. 2,3 and 5.
Insufficient.

2) 4K= \(P^a\)*\(Q^b\)*\(R^c\)
Same values of K can be used as above. Insufficient.

1+2) Both statements provide the same information. Insufficient.

Answer is E.
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ykaiim
If K is a positive integer, how many different prime numbers are factors of the expression \(K^2\)?

1) Three different prime numbers are factors of \(4K^4\).
2) Three different prime numbers are factors of 4K.

We need to determine the number of different prime factors in K^2. We must remember that the number of distinct prime factors of K^n for any positive integer n is same as the number of distinct prime factors of K. Thus, K^2 has the same distinct prime factors as K. That is, if we know the number of distinct prime factors K has, then we know the number of distinct prime factors K^2 has.

Statement One Alone:

Three different prime numbers are factors of 4K^4.

The information in statement one is not sufficient.

For instance, if K = 2 x 3 x 5, then 4K^4 has 3 different prime factors and K^2 also has 3 different prime factors (since K has 3 different prime factors). However, if K = 3 x 5, then 4K^2 has 3 different prime factors; however, K^2 has 2 different prime factors (since K has 2 different prime factors).

Statement Two Alone:

Three different prime numbers are factors of 4K.

The information in statement two is not sufficient.

For instance, if K = 2 x 3 x 5, then 4K has 3 different prime factors and K^2 has 3 different prime factors. However, if K = 3 x 5, then 4K has 3 different prime factors; however, K has 2 different prime factors.

Statements One and Two Together:

We see that using both statements still allows for K to have 2 or 3 different prime factors.

Answer: E
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