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Bunuel

FRESH GMAT CLUB TESTS QUESTION



If k is an integer, is \(\frac{1}{2^{1-k}} < \frac{1}{8}\) ?

(1) k is a prime number
(2) k^2 + 1 is a prime number


#1
k is a prime number
k will always be +ve so value of \(\frac{1}{2^{1-k}} < \frac{1}{8}\)
shall always be NO
sufficient
#2
k^2 + 1 is a prime number
here k can both be + or -ve
so we get both yes and no ; insufficient
IMO A
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Bunuel

FRESH GMAT CLUB TESTS QUESTION



If k is an integer, is \(\frac{1}{2^{1-k}} < \frac{1}{8}\) ?

(1) k is a prime number
(2) k^2 + 1 is a prime number

\(k=integer…\frac{1}{2^{1-k}} < \frac{1}{8}…2^{-(1-k)}<2^{-3}…-1+k<-3…Question:k<-2?\)

(1) k is a prime number sufic.

\(k=prime…k≥2…Answer: no\)

(2) k^2 + 1 is a prime number insufic.

\(k^2=[1,4,16…]…k^2+1=[2,5,17]…k=[|1|,|2|,|4|,…]…Answer:yes/no\)

Answer (A)
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