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# If k > n, is kx - nx > p - m?

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Intern
Joined: 24 May 2018
Posts: 6
If k > n, is kx - nx > p - m?  [#permalink]

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12 Sep 2018, 09:12
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Difficulty:

35% (medium)

Question Stats:

74% (01:28) correct 26% (01:29) wrong based on 39 sessions

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If k > n, is kx - nx > p - m?

(1) x = 7/3
(2) k - p > n - m
Director
Joined: 20 Feb 2015
Posts: 795
Concentration: Strategy, General Management
Re: If k > n, is kx - nx > p - m?  [#permalink]

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12 Sep 2018, 09:31
jennysussna wrote:
if k > n, is kx - nx > p - m?
1) x=7/3
2) k - p > n - m

1) x=7/3
above equation can be written as
x(k-n) > (p-m)
we do not know any other value apart from x
insufficient

2) k - p > n - m
can be rearranged
k-n > p-m

may seem sufficient , but we do not know value of x (various combinations of +ve and -ve numerator and denominators are possible)
insufficient

using both
we have x
so we have a definite yes
x(k-n) > (p-m)
sufficient
C
Director
Joined: 12 Feb 2015
Posts: 842
Re: If k > n, is kx - nx > p - m?  [#permalink]

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13 Sep 2018, 08:34
Each statement alone does not give any information about few variables but together they give complete information.

It is a straight forward C.
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Posts: 267
Re: If k > n, is kx - nx > p - m?  [#permalink]

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13 Sep 2018, 09:41
jennysussna wrote:
If k > n, is kx - nx > p - m?

(1) x = 7/3
(2) k - p > n - m

OA:C

$$k>n, \quad$$Is $$x*(k - n) > p - m$$ ?

$$(1) \quad x= \frac{7}{3}$$

Let $$k-n = 3$$, and $$p-m=1$$ then L.H.S$$= \frac{7}{3}*3$$;R.H.S $$=1$$

L.H.S>R.H.S
Is $$kx - nx > p - m?$$ : Yes

Let $$k-n = 3$$, and $$p-m=8$$ then L.H.S$$= \frac{7}{3}*3$$;R.H.S $$=8$$

L.H.S<R.H.S
Is $$kx - nx > p - m?$$ : No

Statement $$(1)$$ alone is insufficient.

$$(2)\quad k - p > n - m$$

$$k-n>p-m$$

$$x$$ can be a fraction less than $$1$$, negative or positive.

Statement $$(2)$$ alone is insufficient.

Combining $$(1)$$ and $$(2)$$, we get $$\frac{7}{3}(k-n)>p-m$$.
So combining statement $$(1)$$ and $$(2)$$ will be sufficient
Re: If k > n, is kx - nx > p - m?   [#permalink] 13 Sep 2018, 09:41
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# If k > n, is kx - nx > p - m?

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