blog wrote:
If L and K are lines in xy- plane, is the product of the slope of L and K equal to -1?
(1) Line L passes through the origin and the point (1,2).
(2) Line K has x-intercept 4 and y-intercept 2.
IMPORTANT: For geometry and coordinate plane Data Sufficiency questions, we are often checking to see whether the statements
"LOCK" a particular line, angle, length, or shape into having just one possible position or measurement. This concept is discussed in much greater detail in the video below.
Target question: Is the product of the slopes of l and k equal to -1?IMPORTANT: The product of the slopes will equal -1 if the lines are perpendicular to each other (unless the two lines are horizontal and vertical, in which case the product will equal zero). This allows us to REPHRASE the target question as...
REPHRASED target question: Are the two lines perpendicular to each other? Statement 1: Line l passes through the origin and the point (1, 2) NOTICE that statement 1 LOCKS line l into ONE AND ONLY ONE line.
That said, we have no information about line k, so
we cannot determine whether the two lines are perpendicular to each other.
Since we cannot answer the
REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: Line k has x-intercept 4 and y-intercept 2. NOTICE that statement 1 LOCKS line k into ONE AND ONLY ONE line.
That said, we have no information about line l, so
we cannot determine whether the two lines are perpendicular to each other.
Since we cannot answer the
REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Statement 1 LOCKS in the shape of line l
Statement 2 LOCKS in the shape of line k
So,
we COULD very well determine whether or not the two lines are perpendicular to each otherSince we can answer the
REPHRASED target question with certainty, the combined statements are SUFFICIENT
Answer: C
RELATED VIDEO
, regarding line K of (4,0) (0,2), it seems the line can be drawn either vertically or horizontally on point of (4,2). Therefore it doesn't seem line K is perpendicular to line L at the crossing point unless is at the origin point? Have I missed something in the reasoning here?
Also not quite sure with question asked is the product of the slope of L and K equal to -1? Since we got slope = -1/2. Where or how is the product here? Thanks Brent