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Senior Manager  Joined: 20 Aug 2015
Posts: 386
Location: India
GMAT 1: 760 Q50 V44 If m is not equal to k, is |x^2 - y^2| > 0?  [#permalink]

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Difficulty:   75% (hard)

Question Stats: 49% (02:20) correct 51% (02:02) wrong based on 82 sessions

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If $$m\neq{k}$$, is $$|x^2 - y^2| > 0$$?

(1) $$(x+m)^2 = (y+m)^2$$
(2) $$(x+k)^2 = (y+k)^2$$
Math Expert V
Joined: 02 Aug 2009
Posts: 8006
Re: If m is not equal to k, is |x^2 - y^2| > 0?  [#permalink]

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TeamGMATIFY wrote:
If $$m\neq{k}$$, is $$|x^2 - y^2| > 0$$?

(1) $$(x+m)^2 = (y+m)^2$$
(2) $$(x+k)^2 = (y+k)^2$$

Hi,
the Q should make it to 600 level Qs..

lets see the info from Q stem

$$|x^2 - y^2| > 0$$...
|x^2 - y^2| is always positive so will always be equal to or greater than 0..
here if we can say that x and y are not of same numeric value irrespective of sign, the answer will be YES..
and If their mod are same, answer is NO as it will be equal to 0..

lets check the statements

(1) $$(x+m)^2 = (y+m)^2$$
$$x^2 + 2xm + m^2 = y^2 + 2ym + m^2$$..
$$x^2-y^2+2xm-2ym=0$$..
$$(x-y)(x+y)+2m(x-y)=0$$..
$$(x+y+2m)(x-y)=0$$..
either x=y, or x+y=-2m...
so either x=y or both may not be equal..
insuff..

(2) $$(x+k)^2 = (y+k)^2$$
same as (1)..
$$(x+y+2k)(x-y)=0$$..
either x=y, or x+y=-2k...
so either x=y or both may not be equal..
insuff..

Combined..
we have x+y= -2m=-2k, BUT $$m\neq{k}$$..
so only possiblity common in two statements is x=y..
so ans is NO..
SUFF
C
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Re: If m is not equal to k, is |x^2 - y^2| > 0?  [#permalink]

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TeamGMATIFY wrote:
If $$m\neq{k}$$, is $$|x^2 - y^2| > 0$$?

(1) $$(x+m)^2 = (y+m)^2$$
(2) $$(x+k)^2 = (y+k)^2$$

I have a small doubt here

can we write (X+M)^2 = IX+MI or distance between X & M.... CEO  S
Joined: 20 Mar 2014
Posts: 2595
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44 GPA: 3.7
WE: Engineering (Aerospace and Defense)
If m is not equal to k, is |x^2 - y^2| > 0?  [#permalink]

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rohit8865 wrote:
TeamGMATIFY wrote:
If $$m\neq{k}$$, is $$|x^2 - y^2| > 0$$?

(1) $$(x+m)^2 = (y+m)^2$$
(2) $$(x+k)^2 = (y+k)^2$$

I have a small doubt here

can we write (X+M)^2 = IX+MI or distance between X & M.... Not unless x=m=0 or any other similar condition. The only thing common (generally) between (x+m)^2 and |x+m| is that both the expressions will yield a non negative value.

Hope this helps.
Math Revolution GMAT Instructor V
Joined: 16 Aug 2015
Posts: 8027
GMAT 1: 760 Q51 V42 GPA: 3.82
Re: If m is not equal to k, is |x^2 - y^2| > 0?  [#permalink]

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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If m≠k , is |x ^2 −y ^2 |>0 ?

(1) (x+m)^2 =(y+m) ^2
(2) (x+k) ^2 =(y+k) ^2

When you modify the original condition and the question, they become x^2=/y^2?. Then, there are 4 variables(m,k,x,y), which should match with the number of equations. So you need 4 equations. For 1) 1 equation, for 2) 1 equation, which is likely to make E the answer.
When 1) & 2), they become 1) x+m=y+m, x+m=-y-m, x+k=y+k, x+k=-y-k. That is, from x=y, x+y=-2m=-2k, m is not k, which only satisfies x=y. Then, the question is no to x^2=/y^2?, which is sufficient. Therefore, the answer is C.

 For cases where we need 2 more equations, such as original conditions with “2 variables”, or “3 variables and 1 equation”, or “4 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 70% chance that C is the answer, while E has 25% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since C is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, D or E.
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Re: If m is not equal to k, is |x^2 - y^2| > 0?  [#permalink]

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_________________ Re: If m is not equal to k, is |x^2 - y^2| > 0?   [#permalink] 30 Mar 2019, 23:18
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