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If m, n and p are nonzero digits and mn = p. What is p? (1) n < m (2)

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If m, n and p are nonzero digits and mn = p. What is p? (1) n < m (2) [#permalink]

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If m, n and p are nonzero digits and mn = p. What is p?

(1) n < m
(2) m = 5
[Reveal] Spoiler: OA

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If m, n and p are nonzero digits and mn = p. What is p? (1) n < m (2) [#permalink]

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duahsolo wrote:
If m, n and p are nonzero digits and mn = p. What is p?

(1) n < m
(2) m = 5


we know that the product of two integers between 1 and 9 has to be an integer between 1 and 9

( 1) n < m Insufficient ===> there are several possibilities as 1*2=2 or 2*3=3 and p can be any integer between 1 and 9

(2) m = 5 SUFFICIENT =>>> the only integer which can multiplicate 5 and give an integer between 1 and 9 is 1
therefore, P is equal to 5


answer B
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Re: If m, n and p are nonzero digits and mn = p. What is p? (1) n < m (2) [#permalink]

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New post 25 Oct 2016, 19:40
damybox wrote:
duahsolo wrote:
If m, n and p are nonzero digits and mn = p. What is p?

(1) n < m
(2) m = 5


we know that the product of two integers between 1 and 9 has to be an integer between 1 and 9

( 1) n < m Insufficient ===> there are several possibilities as 1*2=2 or 2*3=3 and p can be any integer between 1 and 9

(2) m = 5 SUFFICIENT =>>> the only integer which can multiplicate 5 and give an integer between 1 and 9 is 1
therefore, P is equal to 5



answer B


Hi duahsolo
Could u please confirm the OA

since it is nowhere written that m,n,p are +ve integers then n could be 1 or -1
thus p could be 5 or -5
Both statements are not suff...

Ans E

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If m, n and p are nonzero digits and mn = p. What is p? (1) n < m (2) [#permalink]

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New post 25 Oct 2016, 22:52
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rohit8865 wrote:
damybox wrote:
duahsolo wrote:
If m, n and p are nonzero digits and mn = p. What is p?

(1) n < m
(2) m = 5


we know that the product of two integers between 1 and 9 has to be an integer between 1 and 9

( 1) n < m Insufficient ===> there are several possibilities as 1*2=2 or 2*3=3 and p can be any integer between 1 and 9

(2) m = 5 SUFFICIENT =>>> the only integer which can multiplicate 5 and give an integer between 1 and 9 is 1
therefore, P is equal to 5



answer B


Hi duahsolo
Could u please confirm the OA

since it is nowhere written that m,n,p are +ve integers then n could be 1 or -1
thus p could be 5 or -5
Both statements are not suff...

Ans E


Hi rohit8865,

I can confirm that the OA is B.

Notice that m, n & p must be nonzero DIGITS, which could only be 1, 2, 3, 4, 5, 6, 7, 8, or 9 (I'm not sure of negative digits).

Hope this helps.
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Re: If m, n and p are nonzero digits and mn = p. What is p? (1) n < m (2) [#permalink]

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Re: If m, n and p are nonzero digits and mn = p. What is p? (1) n < m (2)   [#permalink] 18 Dec 2017, 09:04
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