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Re: If n+10^3/ m+33=4 and m=10, then n/m=? [#permalink]
Substituting m=10 in equation
We get
n-1000=80

N=-920

n/m=-920/10= -92

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Re: If n+10^3/ m+33=4 and m=10, then n/m=? [#permalink]
uzouka123
If \(\frac{(n+10^3)}{(m+10)}=4\) and m=10, then \(\frac{n}{m}\)= ?

(A) -92
(B) 4-10^-2
(C) 4x10^2
(D) 4
(E) 99



\(\frac{(n+10^3)}{(m+10)}=4\)

Or, \(n + 1000 = 4(10 + 10)\)

Or, \(n + 1000 = 80\)

So, \(n = -920\)

Now, \(\frac{n}{m}\)= \(\frac{-920}{10}\) = \(-92\) , Answer must be (A)
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Re: If n+10^3/ m+33=4 and m=10, then n/m=? [#permalink]
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Re: If n+10^3/ m+33=4 and m=10, then n/m=? [#permalink]
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