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If n = 4p, where p is a prime number greater than 2, how many differen

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Re: If n = 4p, where p is a prime number greater than 2, how many differen  [#permalink]

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New post 26 Sep 2018, 22:36
Would this be an acceptable way of solving:

Prime factor the 4 that is next to p
Prime factorization gives us 2^1 and 2^1
Using only Even primes with above Powers of 1, we just add 1 to the power of each and multiply - this would give us different combinations of even factors
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GMAT 1: 640 Q47 V32
If n = 4p, where p is a prime number greater than 2, how many differen  [#permalink]

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New post 01 Apr 2019, 13:32
n = 2*2*p
p = odd when greater than 2, so only 2^1*2^1 are even and will have even divisors.

Formula for finding factors (factors of even number will also be even):
Factors = (1+1)*(1+1) = 2*2 = 4
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Re: If n=4p, where p is a prime number greater than 2. How many  [#permalink]

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Re: If n=4p, where p is a prime number greater than 2. How many   [#permalink] 23 Sep 2019, 06:05

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