SwethaReddyL
Bunuel,
I did, n=2^2p, and since p is prime greater than 2, it won't have even factors. So I calculated the total factors of even, as 2+1=3
Why is that wrong? isn't it how you calculate the no of factors?
The mistake is that p being odd does not mean it cannot appear in an even divisor.
An even divisor just needs at least one factor of 2. Since n = 2^2 * p, the exponent of 2 can be 1 or 2, and the exponent of p can be 0 or 1.
So the even divisors are 2, 4, 2p, and 4p.
There are 4 even divisors.
Answer: C.