Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Want to score 90 percentile or higher on GMAT CR? Attend this free webinar to learn how to pre-think assumptions and solve the most challenging questions in less than 2 minutes.
Want to solve 700+ level Algebra questions within 2 minutes? Attend this free webinar to learn how to master the most challenging Inequalities and Absolute Values questions in GMAT
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
Show Tags
Updated on: 02 Jun 2014, 01:59
6
7
n= 4p = 2^2*p^1 so total no. of factors: (2+1)*(1+1)= 6 total no. of odd factors, since p is odd as it is a prime>2: p^1 and p^0 = 2 Total no. of even factors: 6 - 2 = 4
Now if n was n=4pq where p and q are both prime no.s greater than 2 then: total no. of factors: (2+1)*(1+1)*(1+1)= 12 total no. of odd factors, since p is odd as it is a prime>2: (1+1)*(1+1)= 4 Total no. of even factors: 12 - 4 = 8
Hi Bunuel, could you validate my logic pls?
_________________
Please contact me for super inexpensive quality private tutoring
My journey V46 and 750 -> http://gmatclub.com/forum/my-journey-to-46-on-verbal-750overall-171722.html#p1367876
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
Show Tags
21 Apr 2013, 00:04
Is one not a divisor?
_________________
You've been walking the ocean's edge, holding up your robes to keep them dry. You must dive naked under, and deeper under, a thousand times deeper! - Rumi
http://www.manhattangmat.com/blog/index.php/author/cbermanmanhattanprep-com/ - This is worth its weight in gold
Economist GMAT Test - 730, Q50, V41 Aug 9th, 2013 Manhattan GMAT Test - 670, Q45, V36 Aug 11th, 2013 Manhattan GMAT Test - 680, Q47, V36 Aug 17th, 2013 GmatPrep CAT 1 - 770, Q50, V44 Aug 24th, 2013 Manhattan GMAT Test - 690, Q45, V39 Aug 30th, 2013 Manhattan GMAT Test - 710, Q48, V39 Sep 13th, 2013 GmatPrep CAT 2 - 740, Q49, V41 Oct 6th, 2013
GMAT - 770, Q50, V44, Oct 7th, 2013 My Debrief - http://gmatclub.com/forum/from-the-ashes-thou-shall-rise-770-q-50-v-44-awa-5-ir-162299.html#p1284542
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
Show Tags
02 Jun 2014, 00:04
2
MensaNumber wrote:
n= 4p = 2^2*p^1 so total no. of factors: (2+1)*(1+1)= 6 total no. of odd factors, since p is odd as it is a prime>2: p^1 and p^0 = 2 Total no. of even factors: 6 - 2 = 4
Now if n was n=4pq where p and q are both prime no.s greater than 2 then: total no. of factors: (2+1)*(1+1)*(1+1)= 12 total no. of odd factors, since p is odd as it is a prime>2: (1+1)*(1+1)= 4 Total no. of even factors: 12 - 4 = 8
Status: No dream is too large, no dreamer is too small
Joined: 14 Jul 2010
Posts: 402
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
Show Tags
17 Apr 2015, 02:36
if we apply theory of finding number of divisor Let,s plug in p= 3 then n= 12 Factor of 12 are 3, 2, 2 p>2, so 2s are out Now the formula (p+1)+(q+1)+(r+1) = 3+1 = 4 Ans C
_________________
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
Show Tags
27 Jul 2015, 01:10
ITMRAHUL wrote:
If n=4p, where p is a Prime number greater than 2, how many different positive even divisors does n have including n?
a) 2 b) 3 c) 4 d) 6 e) 8
can some 1 throw light on it?
@p=3, n = 4*3 = 12, Positive Even divisor of n = {2, 4, 6, 12} i.e. 4 Divisors @p=5, n = 4*5 = 20, Positive Even divisor of n = {2, 4, 10, 20} i.e. 4 Divisors @p=7, n = 4*7 = 28, Positive Even divisor of n = {2, 4, 14, 28} i.e. 4 Divisors @p=11, n = 4*11 = 44, Positive Even divisor of n = {2, 4, 22, 44} i.e. 4 Divisors @p=13, n = 4*13 = 52, Positive Even divisor of n = {2, 4, 26, 52} i.e. 4 Divisors and so on...
Answer: option C
_________________
Prosper!!! GMATinsight Bhoopendra Singh and Dr.Sushma Jha e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772 Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi http://www.GMATinsight.com/testimonials.html
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
Show Tags
13 Jul 2016, 07:39
Walkabout wrote:
If n = 4p, where p is a prime number greater than 2, how many different positive even divisors does n have, including n ?
(A) Two (B) Three (C) Four (D) Six (E) Eight
This is an interesting question because we are immediately given the option to insert any prime number we wish for p. Since this is a problem-solving question, and there can only be one correct answer, we can select any value for p, as long as it is a prime number greater than 2. We always want to work with small numbers, so we should select 3 for p. Thus, we have:
n = 4 x 3
n = 12
Next we have to determine all the factors, or divisors, of P. Remember the term factor is synonymous with the term divisor.
1, 12, 6, 2, 4, 3
From this we see that we have 4 even divisors: 12, 6, 2, and 4.
If you are concerned that trying just one value of p might not substantiate the answer, try another value for p. Let’s say p = 5, so
n = 4 x 5
n = 20
The divisors of 20 are: 1, 20, 2, 10, 4, 5. Of these, 4 are even: 20, 2, 10 and 4. As we can see, again we have 4 even divisors.
No matter what the value of p, as long as it is a prime number greater than 2, n will always have 4 even divisors.
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
Show Tags
28 Dec 2016, 08:16
One of those Quality Questions from the Official Guide. here is my solution => Method 1-> n=2^2*p as p is a odd prime (all primes >2 are odd) number of even factors => 2*2-> four Four factors are -> 2,4,2p,4p Alternatively let p=3 so n=12 factors => 1,2,3,4,6,12 even factors => 2,4,6,12 hence four
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
Show Tags
01 Apr 2017, 07:09
n=4p Let;s factorize n n= 2^2 * p^a (a is some positive power of p and we know that p is a prime number greater than 2 i.e. it is odd as the only even prime number is 2. So we don't have to worry about the power of p as it would yield odd integer and we have to just find even factors.)
Thus the answer is 2, 4(2^2), 2p (even), and 4p (even).
gmatclubot
Re: If n = 4p, where p is a prime number greater than 2, how many differen
[#permalink]
01 Apr 2017, 07:09
close
57% (01:22) correct 
