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If n is a positive integer greater than 2, what is the value of n ?
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16 Jan 2020, 23:02
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Competition Mode Question If n is a positive integer greater than 2, what is the value of n ? (1) The tens' digit of 11^n is 4. (2) The hundreds' digit of 5^n is 6. Are You Up For the Challenge: 700 Level Questions
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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 01:02
If n is a positive integer greater than 2, what is the value of n ?
11 ^3 = 1331 11^4 = 14641
so, n can be 4 or other values (1) The tens' digit of 11^n is 4.  seems n=4, so sufficient. (2) The hundreds' digit of 5^n is 6.  again seems n =4, so sufficient.
Imo. D



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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 01:16
Quite hard question. The question is n=? Provided information  n = integers+  n>2  so n is basically 3,4,5,... (1) The tens' digit of 11^n is 4 tens' digit = 4 means that the number is somemthing like this _ _ _ _ _ 4 _  what I did is to fastly calculate the products of 11  11^1 = 1111^2 = 1 2111^3 = 13 3111^4 = 146 41 OK! I know that if n=4 is the only answer, then the answer is sufficient  At first I think A is ok, but when I think closely, I see the pattern, and I believe that the number is going to be a loop, so that the tens digit is going to be like 1,2,3,4,...,9,0,1,2,3,4,...  I try to prove myself by calculating 91*11 and the result is something end with 01, and 01*11 is end with 11! so the loop is surely happened!  with this calculation, I know that there is going to be more than one number for n to have 11^n that has tens' digit of 4  So it is Not sufficient (2) The hundreds' digit of 5^n is 6 hundreds' digit = 6 means that the number is somemthing like this _ _ _ _ 6 _ _  I approach the same way with the first question by trying to input number to see pattern  5^2 = 255^3 = 1 255^4 = 625 Yes! this is the one  Then I start to ask myself about the loop again, would it has a loop? So I try to input a little more number  5^5 = ...125 Gotcha! we found the loop. And I know that there is going to be more than one number of n to have 5^n with the hundred digit of 6  So it is not sufficient (3)We try to think about both (1)&(2) So the number should be when 11^n = _ _ _ 4 _ 5^n = _ _ 6 _ _  from the previous calculation, I know that when n=4, it is sufficient in both (1) & (2) since 11^4 = 146 41 5^4 = 625  but then the question popup, I ask myself " Would n=4 be the only number? or are there any matching numbers after that?"  since I have already waste a lot of time, I have to think fast. I recognize the pattern that for 11^n, the number for tens digit that equal to 4 is happened in the pattern n=4,14,24,34,... (since the 11^n pattern of tens digit runs from 0,1,2,3,4,..,9,0,1,... so that the number reach the loop every 10 numbers) for 5^n, that the number for hundreds digit that equal to 6 is happened in the pattern n=4,6,8,10,12,14... (sine the 5^n pattern of hundred digits runs from 1,6,1,6,1,6,... so that the number reach the loop every 2 numbers)  So I think my answer should be E. This is because n could be 4,14,24,... and still suffice both (1) and (2), and that we can not find the exact number of n. (I hope I am correct If I am wrong please give me suggestions. But to be honestly, at first, I answer A which is totally wrong) My learning we usually remember about the unit digits pattern when odd/even integers expotent eg. in every 4 pattern Odd1^4=1 3^4=1 5^4=5 (exceptional) 7^4=1 9^4=1 Even2^4=6 4^4=6 6^4=6 8^4=6 10^4=0 (exceptional) But now we know that there are also pattern in tens, hundreds digits that could occur a loop. We dont have to remember every answer numbers. Just remember that there are loops about them.  When we have to prove the numbers, we dont really need to calculate all of it, or we are running out of time, we just anticipate the future pattern (like for 5 the loop happens every 2 numbers, and for 11 the loop happens every 10 numbers)



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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 01:38
#1 The tens' digit of 11^n is 4. possible at n = 4 sufficient #2 The hundreds' digit of 5^n is 6. possible at n = 4,6 insufficient IMO A
If n is a positive integer greater than 2, what is the value of n ?
(1) The tens' digit of 11^n is 4. (2) The hundreds' digit of 5^n is 6.



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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 01:52
1) n=4,14,24,... NOT SUFFICIENT
2) n=4,6,8,...,14,... NOT SUFFICIENT
1)+2) n=4,14,24,... NOT SUFFICIENT
FINAL ANSWER IS (E)
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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 02:09
If n is a positive integer greater than 2, what is the value of n ? Constraint: n>2 Asked : n=? (1) The tens' digit of 11^n is 4. 11^4 = 146 41 Any other value of n will give us tens digit of n E.g. 11^5 = 1610 51 tens digit us 5 (Sufficient) (2) The hundreds' digit of 5^n is 6.5^4= 625 5^6= 15 625 Both have hundreds digit as 6 so n =4/6 (Not sufficient) Hit that A Posted from my mobile device



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If n is a positive integer greater than 2, what is the value of n ?
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Updated on: 20 Jan 2020, 04:38
Quote: If n is a positive integer greater than 2, what is the value of n ?
(1) The tens' digit of 11^n is 4. (2) The hundreds' digit of 5^n is 6. n = positive integer > 2 (1) The tens' digit of 11^n is 4. insufic11 * ABC = A(A+B)(B+C)C 11 * 121 = 1(3)(3)1 = 1331 11^1=11…^2=121…^3=1331…^4=14641… ^5=x51…^6=x61…^7=x71…^8=x81… ^9=x91…^10=x01…^14=x41…^24=x41… n=4,14,24… (2) The hundreds' digit of 5^n is 6. insufic5^1=5…^2=25…^3=(125)…^4=(625)…^5=3(125)… ^6=15(625)…^7=x125…^8=x(625)… n=4,6,8…evens (1&2) insuficn=4,14,24… Ans (E)
Originally posted by exc4libur on 17 Jan 2020, 04:53.
Last edited by exc4libur on 20 Jan 2020, 04:38, edited 2 times in total.



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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 07:27
(1) The tens' digit of 11^n is 4. \(11^1 = 11\) \(11^2 = 121\) \(11^3 = 1331\) \(11^4 = 14641\)
. . . \(11^{14} = xxxxxx41\) \(11^{15} = xxxxxx51\)
So, Possible values of n = {4, 14, 24, 34, . . . . } —> Insufficient
(2) The hundreds' digit of 5^n is 6. \(5^3 = 125\) \(5^4 = 625\) \(5^5 = 3125\) \(5^6 = 15625\)
So, for every even power of 5, hundred’s digit = 6 —> Possible values of n = {4, 6, 8, 10, 12, . . . } —> Insufficient
Combining (1) & (2), Possible values of n = {4, 14, 24, . . . . } —> Insufficient
Option E
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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 10:04
From statement (1), 11 x 11 x 11 x11 = 1241, ten’s digit is 4 when n =4
From statement (2), 5 x 5 x 5 x 5 = 625, hundred’s digit is 6 when n = 4.
In both statements, Answer:D



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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 10:22
If n is a positive integer greater than 2, what is the value of n ? n > 2, n = ? (1) The tens' digit of \(11^n\) is 4. \(11^4 = 14641\) for n = 4 \(11^14 = ... 41\) for n = 14 (Pattern of 1, 2, 3, 4, 5, 6, 7, 8, 9 & 0 at tens' place is repeated for powers 1, 2, 3, 4, 5, 6, 7, 8, 9 & 0 respectively and 11 to 20 and further ..) INSUFFICIENT. (2) The hundreds' digit of \(5^n\) is 6. \(5^4 = 625\) for n = 4 \(5^6 = 15625\) for n = 6 Here at hundreds' place 1 occurs for odd powers and 6 occurs for even powers. INSUFFICIENT. Together 1 and 2. n = 4 or 14 or 24 etc.. INSUFFICIENT. Answer E.
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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 20:18
If n is a positive integer greater than 2, what is the value of n ?
(1) The tens' digit of 11^n is 4. (2) The hundreds' digit of 5^n is 6
1) If we notice the values of exponents of 11, we can see the ten's digit represent the power of 11, like 11^2 = 121, 11^3= 1331, 11^4= 14641, 11^5= 161051...so this pattern will repeat and hence there can be more than one value for n. insufficient.
2) 5^3 =125, 5^ 4 = 625, 5^5 = 3125, 5 ^6= 15625...so here the pattern is 1 when the power is odd and 6 when the power is even. so no single value is possible. insufficient.
Together, n can be any integer with the unit digit of 4. insufficient.
E is the answer.



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Re: If n is a positive integer greater than 2, what is the value of n ?
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17 Jan 2020, 20:23
(1) The tens' digit of 11^n is 4. tens and units digit of 11^n is n=3, ..31 n=4, ..41 n=5 is ...51 and so on.. n can be 4, 14,... Insufficient
(2) The hundreds' digit of 5^n is 6. when n =3, number is 125 n=4, it is 625 n=5, is 3125 n=6, it is 10625 After every two terms 6 appears in the hundreds place Insufficient
(1)+(2); n=4, 14,... Insufficient
E is correct



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Re: If n is a positive integer greater than 2, what is the value of n ?
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18 Jan 2020, 03:55
If n is a positive integer greater than 2, what is the value of n ?
(1) The tens' digit of 11^n is 4. 11^4 yeild a 4 in the tens' digit but so does 11^14 11^24 11^34... insufficient
(2) The hundreds' digit of 5^n is 6. 5^4 yield a hundreds' digit of 6 and so does all the even number after 2 eg. 5^6 5^8 ... insufficient
together, insufficient, N can be 4, 14, 24, 34 ...more
E



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Re: If n is a positive integer greater than 2, what is the value of n ?
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18 Jan 2020, 14:05
If n is a positive integer greater than 2, what is the value of n ?
(Statement1): The tens' digit of \(11^n\) is 4. \(11^1= 11\) \(11^2= 121\) \(11^3= ...31\) \(11^4= ...41\) .... \(11^{10}= ...01\) \(11^{11} = ...11\) \(11^{12}= ...21 \) —> So, n could be 4, 14, 24.... Insufficient
(Statement2): The hundreds' digit of \(5^n\) is 6. \(5^{3} = 125\) \(5^{4} = 625\) \(5^{5} = ...125 \) \(5^6 = ...625\) \(5^7= ...125\) —> n could be 4,6,8,10.... Insufficient
Taken together 1&2, n could be 4,14, 24 ... so on Insufficient
The answer is E
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Re: If n is a positive integer greater than 2, what is the value of n ?
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19 Jan 2020, 20:47
Ans: E
11^4 & 11^14= tens digit 4 5^4 & 5^14= hundreds digit 6
Both not sufficient.




Re: If n is a positive integer greater than 2, what is the value of n ?
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