If n is a positive integer, is (n+1)! - (n-1)! greater than

Question

If n is a positive integer, is (n+1)! - (n-1)! greater than (n+1)!/(n-1)! ?
1) Square root of n is a positive integer
2) n is divisible by 2

cloudz9 · Answer

Statement (1) does not give any useful information that i can see

(n+1)!-(n-1)! is greater than (n+1)!/(n-1)! for any positive number except 1 (as (n-1)! would be 0...i think!...thus making (n+1)!/(n-1)! undefined).
If n is divisible by 2...the lowest possible value of n is two...
this is sufficient to say (n+1)!-(n-1)! > (n+1)!/(n-1)!

thus, my answer is B

Vithal · Answer

the whole equation reduces to (n-1)! * (n(n+1) -1) ... this needs to be compared with (n+1)!/(n-1)! = n(n+1)

I) Square root of n is a positive integer 
n can be 1 or 2 or any number greater than 2

for n =1 0! =1 (not zero) - LHS will be less than RHS
for n = 2, LHS < RHS
for n - 3, LHS = 2*11 ; RHS = 12 => LHS > RHS
and for any number greater than 2, LHS > RHS

We need (2) to determine that n is greater than 2

(2) only this is not sufficient either as n can be equal to 2

and hence C

cloudz9 · Answer

yeah true sorry
made a stupid mistake

agree with C then

HIMALAYA · Answer

yah, agree with C. if n <3, second term is larger. if n>2, the first term is larger. 

togather, n >2. so it is sufficient.

sparky nice problem..............

FN · Answer

How is it C! I am coming up with E

we need to know that if N is positive, greater than 2.....

I know it is positive from both statements, but dont know if it is greater than 2?

rthothad · Answer

I will go with C too
The equation reduces to (n-1)!  > n(n+1)
From statement 1: n can be 1, 4, 9,...
when n is 1: (n-1)!  is not > than n(n+1)
when n is 4: (n-1)!  is > than n(n+1)
when n is 9: (n-1)!  is > than n(n+1)
so statement 1 is not sufficient

From statement 2: n can be any even number such as 2, 4, 6, 8....
when n is 2: (n-1)!  is not > than n(n+1)
when n is 4: (n-1)!  is > than n(n+1)
so statement 2 is not sufficient

But both put together: n can be 4, 16, .....
As shown above the condition is satisfied for any number greater than 2
Hence C

AJB77 · Answer

The two values can be equal, or one can be greater than the other.

For n=1, the values are equal

For n=2, LHS < RHS

For n > 2 LHS < RHS

So we need to find if n=1 or n=2 or n > 2

I alone gives us not enough information. n could be 1,4,9 etc.

II alone gives us not enough information n could be 2,4,6 etc.

I&II together say that n could be 4,16,36 etc. which is sufficient to determine that LHS < RHS

So I'll go for C

tarungmat · Answer

I will pick B.

Statement 1, it repets nothing but the original condition that n is a positive integer. It behaves differently for 1 and any higher positive integer. Hence Insufficient. Hence rule out option D as well.

Statement 2, says n is even. substraction operation on two positive integer ( Large positive integer- small positive integer) is always greater than division operation on of the same two numbers ( large positive number/small positive number). Hence B is sufficient.

So answer is B. No need to look at C and E.

HowManyToGo · Answer

I think it is C.

The stem reduces to (n-1)!   >   ?

We need to know that if (n-1)! = 1 then it is NO , but if (n-1) ! > 1 then YES.

Since the least n which is a sqaure of a number and a multiple of 2 is 4. (n-1)! > 1 ,hece the aswer is YES always.

HMTG.

tarungmat · Answer

Clarification: I meant in question's context (with factorial ). we will never have a situation 3-2 and 3/2 according to statement 2.
 Please let me know why not B is correct as per my logic.

HongHu · Answer

(n+1)! - (n-1)!=(n-1)!*n*(n+1)-(n-1)! (n+1)!/(n-1)! =n*(n+1) (n+1)! - (n-1)! - (n+1)!/(n-1)! = (n-1)!* -n(n+1) When n<=2, (n-1)!<=1 (n-1)!* -n(n+1)<=n(n+1)-1-n(n+1)=-1<0 When n>=3, (n-1)!>=2 (n-1)!* -n(n+1)>=2n(n+1)-1-n(n+1)=n(n+1)-1>0 (1) n is square of an integer, n could be 1 or 4 or greater, insufficient (2) n is even, n could be 2 or 4 or greater, insufficient Combined, n could only be 4 or greater, sufficient. (It's always >0 when n>=3) (C)

Ozmba · Answer

How can N be 2..N can be 1or 4 or 9
Sq root of 2 is 1.41414 some thing which is not a positive integer

correct me if i am wrong...

Cheers

If n is a positive integer, is (n+1)! - (n-1)! greater than

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