Given that n is a positive integer:
Is n = (Integer)^2 ?
Concept: Any Perfect Square will always be either 1 unit away from a Multiple of 5 on the Number Line or will be a Multiple of 5
A Multiple of 5 will have a Units Digit of 5 or 0.
Any Perfect Square of an Integer can only have the following Units Digits: 0 ; 1 ; 4 ; 5 ; 6 ; 9
Thus, a Number Property that can be inferred from this pattern is that an (Integer)^2 must take the form of:
5k -1 --- or ---- 5k ---- or ---- 5k + 1
where k = some (+)positive integer
Statement 1:
(1) |n – 5m| = 2 for some integer m
The way to read the Modulus is as follows: "the Distance between N and a Multiple of 5 will be exactly 2 Units on the Number Line."
Therefore, given the inference we made above, it can never be true that N will be a Perfect Square
Definite NO - S1 Sufficient
Statement 2:
(2) |n – 7p| = 2 for some integer p.
Using the Distance Interpretation of the Absolute Value Expression and Equation, is it possible for N to be a Perfect Square when:
"N must be exactly 2 Units away on the Number Line from a Multiple of 7"
case 1: N = 9 and P = 1
plugging both values in will satisfy Statement 2 and N = 9 = (3)^2 ------> Answers Question YES
case 2: N =23 and P = 3
plugging both values in will satisfy Statement 2 and N = 23 is NOT the Square of an Integer -----> Answers Question NO
S2 NOT Sufficient
A - S1 Sufficient Alone
Bunuel